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我尝试从 Jonathan Zdziarski 的“黑客和保护 iOS 应用程序”一书中构建一个示例,编译一个包含大量对象文件的示例。但是在编译二进制文件时:

export PLATFORM=/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform
$PLATFORM/Developer/usr/bin/arm-apple-darwin10-llvm-gcc-4.2 -o launchd launchd.o syscalls.o -static -nostartfiles -nodefaultlibs -nostdlib -W1,-e,_main

终端说: Undefined symbols for architecture armv7: "start", referenced from: -u command line option ld: symbol(s) not found for architecture armv7 collect2: ld returned 1 exit status

通常,当缺少库时,会显示此消息,但是我如何找出是哪一个?我很确定,源代码没有问题。

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-arch armv7 -isysroot -L$(SDK) -L$(SDK)/usr/lib/system

于 2013-06-20T06:16:50.977 回答