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我有一个查询，用于获取特定日期和该日期的价格，但现在我想使用类似的东西来获取一周中特定日期的平均价格。

这是我当前的查询，它适用于从名为 availables 的表中提取的特定日期：

SELECT rooms.name, rooms.roomtype, rooms.id, max(availables.updated_at),
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 0, (availables.price*0.66795805223432), '')) AS day1,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 1, (availables.price*0.66795805223432), '')) AS day2,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 2, (availables.price*0.66795805223432), '')) AS day3,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 3, (availables.price*0.66795805223432), '')) AS day4,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 4, (availables.price*0.66795805223432), '')) AS day5,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 5, (availables.price*0.66795805223432), '')) AS day6,
MAX(IF(to_days(availables.bookdate) - to_days('2009-12-10') = 6, (availables.price*0.66795805223432), '')) AS day7,
MIN(spots) as spots
     FROM `availables`
     INNER JOIN rooms
     ON availables.room_id=rooms.id
     WHERE rooms.hotel_id = '5064' AND bookdate
     BETWEEN '2009-12-10' AND DATE_ADD('2009-12-10', INTERVAL 6 DAY)
     GROUP BY rooms.name
     ORDER BY rooms.ppl

我的第一个 stab 不起作用，可能是因为 DAYSOFWEEK 函数与 to_days 有很大不同...

SELECT rooms.id, rooms.name,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 0, (availables.price*0.66795805223432), '')) AS day1,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 1, (availables.price*0.66795805223432), '')) AS day2,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 2, (availables.price*0.66795805223432), '')) AS day3,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 3, (availables.price*0.66795805223432), '')) AS day4,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 4, (availables.price*0.66795805223432), '')) AS day5,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 5, (availables.price*0.66795805223432), '')) AS day6,
MAX(IF(DAYOFWEEK(availables.bookdate) - DAYOFWEEK('2009-12-10') = 6, (availables.price*0.66795805223432), '')) AS day7,rooms.ppl AS spots FROM `availables` 
 INNER JOIN `rooms` ON `rooms`.id = `availables`.room_id 
 WHERE (rooms.hotel_id = 5064 AND rooms.ppl > 3 AND availables.price > 0 AND availables.spots > 1) 
 GROUP BY rooms.name
 ORDER BY rooms.ppl

也许我让这变得疯狂，有人知道一个更简单的方法。

它需要看起来像这样的数据

#Availables
id    room_id   price    spots    bookdate
1     26        $5       5        2009-10-20
2     26        $6       5        2009-10-21

至：

+----+-------+--------------------+---------------------+---------------------+---------------------+------+------+------+------+
| id | spots | name               | day1                | day2                | day3                | day4 | day5 | day6 | day7 |
+----+-------+--------------------+---------------------+---------------------+---------------------+------+------+------+------+
| 25 | 4     | Blue Room          | 14.9889786921381408 | 14.9889786921381408 | 14.9889786921381408 |      |      |      |      |
| 26 | 6     | Whatever           | 13.7398971344599624 | 13.7398971344599624 | 13.7398971344599624 |      |      |      |      |
| 27 | 8     | Some name          | 11.2417340191036056 | 11.2417340191036056 | 11.2417340191036056 |      |      |      |      |
| 28 | 8     | Another            | 9.9926524614254272  | 9.9926524614254272  | 9.9926524614254272  |      |      |      |      |
| 29 | 10    | Stuff              | 7.4944893460690704  | 7.4944893460690704  | 7.4944893460690704  |      |      |      |      |
+----+-------+--------------------+---------------------+---------------------+---------------------+------+------+------+---
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1 回答 1

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如果我理解正确，看起来您只需要取出“-DAYOFWEEK('2009-12-10')”，因为 DAYOFWEEK(availables.bookdate) 已经返回一个代表星期几的数字。

此外，DAYOFWEEK 返回数字 1 到 7，而不是 0 到 6，因此您需要进行相应调整。

在内部子查询中执行“GROUP BY room_id, DAYOFWEEK(availables.bookdate)”以按房间和日期对平均价格进行分组，然后在外部查询中进行旋转可能更有效。

于 2009-12-11T02:51:38.787 回答