如何从android代码调用php文件来上传图像和字符串。基本上我想将该图像上传到本地主机并将字符串上传到 MySQL .. 我需要在 php 文件中写入以存储在 MySql db 中的内容
问问题
1209 次
2 回答
1
在客户端
HttpURLConnection connection = null;
DataOutputStream outputStream = null;
DataInputStream inputStream = null;
String pathToOurFile = "path of the image.jpeg";
String urlServer = "http://xxx.xxx.xxx.xxx/uploader.php";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
try {
FileInputStream fileInStream = new FileInputStream(new File(pathToOurFile) );
URL url = new URL(urlServer);
connection = (HttpURLConnection) url.openConnection();
// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
// Enable POST method
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
outputStream = new DataOutputStream( connection.getOutputStream() );
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile +"\"" + lineEnd);
outputStream.writeBytes(lineEnd);
bytesAvailable = fileInStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file
bytesRead = fileInStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInStream.read(buffer, 0, bufferSize);
}
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = connection.getResponseCode();
serverResponseMessage = connection.getResponseMessage();
fileInputStream.close();
outputStream.flush();
outputStream.close();
}
catch (Exception ex)
{
//Exception handling
}
在服务器端,
<?php
$target_path = "./";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "Success";
} else{
echo "Error";
}
?>
于 2013-04-11T07:31:57.323 回答
0
Hope the below will help,
private class MyPost extends AsyncTask<Void,Void,Void>{
@Override
protected Void doInBackground(Void... arg0) {
// TODO Auto-generated method stub
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://yoursite.com/page.php");
try {
// Add your data
EditText txtName = (EditText)findViewById(R.id.txtBusinessName);
EditText txtDesc = (EditText)findViewById(R.id.txtDescription);
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("frmName",txtName.getText().toString() ));
nameValuePairs.add(new BasicNameValuePair("frmDesc", txtDesc.getText().toString()));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
Log.v("Post Status","Code: "+response.getStatusLine().getStatusCode());
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
return null;
}
}
于 2013-04-11T07:28:16.713 回答