cassandra - 无法使用 cassandra-cli 删除超列

Question

[default@keyspace] get fv['user:/file.txt'];
=> (super_column=1365647977415,
     (column=6363, value=0000000000000001, timestamp=1368238637628082)
     (column=6c6d64, value=0000013f79344eb2, timestamp=1368238637628081)
     (column=7362, value=000000000000003a, timestamp=1368238637628083))
=> (super_column=1365653962252,
     (column=6363, value=0000000000000001, timestamp=1368238637727277)
     (column=6c6d64, value=0000013f798fbee6, timestamp=1368238637727276)
     (column=7362, value=0000000000000045, timestamp=1368238637727278))

del fv['user:/file.txt'][1365647977415];
column removed.

get fv['user:/file.txt'];
=> (super_column=1365647977415,
     (column=6363, value=0000000000000001, timestamp=1368238637628082)
     (column=6c6d64, value=0000013f79344eb2, timestamp=1368238637628081)
     (column=7362, value=000000000000003a, timestamp=1368238637628083))
=> (super_column=1365653962252,
     (column=6363, value=0000000000000001, timestamp=1368238637727277)
     (column=6c6d64, value=0000013f798fbee6, timestamp=1368238637727276)
     (column=7362, value=0000000000000045, timestamp=1368238637727278))

这怎么可能？比较器是ByteType，我用过

assume fv comparator as LongType;

Answer 1

问题出在比现在更新的列时间戳中。小心，伙计们。

=> (super_column=1365647977415,
     (column=6363, value=0000000000000001, timestamp=1368238637628082)

1368238637628082 == 2013 年 5 月 11 日星期六 02:17:17 GMT

现在是 2013 年 4 月 11 日星期四 07:10:36 GMT