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似乎我的第二个 MySQL 查询由于未知原因而失败。连接时我没有遇到问题，只有在从 $dbLink->query(); 获取结果时才会出现问题。

$photos = getPhotos(getID($_COOKIE[$uname_cookie], $_COOKIE[$passwd_cookie]));

function getID($uName, $passwd) {
    // Just in case, for modularity :P
    include 'misc.php';
    $query = "SELECT ID FROM Users WHERE UserName = '" . $uName . "' AND Password = '" . $passwd . "';";
    $dbLink = new mysqli($host, $user, $pass, $dbname);
    if ($dbLink->connect_errno) {
        echo "Failed to connect to database: " . $dbLink->connect_error;
        return null;
    } else {
        $results = $dbLink->query($query);
        print_r($results->fetch_array());
        $rows = $results->fetch_array();
        return $rows["ID"];
    }
}

function getPhotos($id) {
    // Just in case, for modularity :P
    include 'misc.php';
    $query = "SELECT Location FROM Photos WHERE UserID = " . $id . ";";
    $dbLink = new mysqli($host, $user, $pass, $dbname);
    if ($dbLink->connect_errno) {
        echo "Failed to connect to database: " . $dbLink->connect_error;
        return null;
    } else {
        $results = $dbLink->query($query);
        print_r($results->fetch_array());
        $rows = $results->fetch_array();
        return $rows["ID"];
    }
}

编辑：通过将 $dbLink 传递给函数 IE getPhotos($id, $dbLink) 得到它

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1 回答 1

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$query = "SELECT Location FROM Photos WHERE UserID = '" . $id . "';";
于 2013-04-10T21:21:05.167 回答