1

使用 Visual Basic 2008 和 Emgu CV，我可以在我的 PC 上捕获网络摄像头的流。我想要做的是连接到一个 IP 摄像机，知道它的 URL，使用 Capture = New Capture()。

这是我的代码：

Imports Emgu.CV
Imports Emgu.CV.Util
Imports Emgu.CV.Structure

Public Class Form1

Dim capturez As Capture = New Capture("rtsp://[IP Address]/mpeg4/media.amp")

Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick

    Dim imagez As Image(Of Bgr, Byte) = capturez.QueryFrame()
    PictureBox1.Image = imagez.ToBitmap()

End Sub

End Class

我收到以下错误：无法从 rtsp://[IP 地址]/mpeg4/media.amp 创建捕获

是否可以使用 Capture = New Capture 来做到这一点？如果没有，他们还有其他方法吗？

谢谢。

4

2 回答 2

1

这是我最终使用的解决方案。它仅适用于 JPEG 网络摄像头（不是 MJPEG），不需要 EmguCV

'Connect To Webcam ----------------------------------------------------------------------
    Dim NumberFrames As Integer = 1
    Dim imgNum = Convert.ToString(FrameNumber)
    Dim sourceURL As String = ("http://91.142.238.200/record/current.jpg?rand=" + imgNum)
    'create HTTP request
    Dim req As HttpWebRequest = HttpWebRequest.Create(sourceURL)
    'get response
    Dim res As HttpWebResponse = req.GetResponse
    'get response stream
    Dim reader As New StreamReader(res.GetResponseStream())
    'read data from stream
    Dim img As Image = Image.FromStream(res.GetResponseStream())
    'get bitmap
    PictureBox1.Image = img
    'Increment frame
    FrameNumber = FrameNumber + 1
    '-----------------------------------------------------------------------------------------
于 2013-08-31T14:34:30.320 回答
0

这个摄像头有ip用户名和密码吗？如果你尝试这样的事情：

Imports Emgu.CV
Imports Emgu.CV.Util
Imports Emgu.CV.Structure

Public Class Form1

Dim capturez As Capture = New Capture("rtsp://username:password@[IP Address]/mpeg4/media.amp")

Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick

Dim imagez As Image(Of Bgr, Byte) = capturez.QueryFrame()
PictureBox1.Image = imagez.ToBitmap()

End Sub


End Class
于 2013-04-12T20:49:29.463 回答