20

I've got this situation where I'm trying to use the <template> tag in my html source:

<template id="some-id">
  <div id="content-container">
    <span>{{some_string}}</span>
  <div>
</template>

This ends up placing the template in the document but it is not considered to be in the DOM. This means that $("#content-container") is not found in browsers that support template tags. If I search for:

$("#some-id")

I get this back:

<template id=​"some-id">​
  #document-fragment
    <div id="content-container">
      <span>{{some_string}}</span>
    <div>
</template>​

None of this surprises me. What I need to know how to do is to clone the contents of the document-fragment and have a fresh node I can then stick into the DOM where I want it.

I have found examples of how to do this w/o jQuery but much of the code around this stuff is already using jQuery and I need to know how to use jQuery to do this.

My first thought was to get the html and then use it to create a new node:

stuff = $("#some-id").html()
new_node = $(stuff)

This results in the following errors:

Error: Syntax error, unrecognized expression: <the html string>

I don't know if the error is caused by the mustache syntax or not. I figure there has to be a jQuery solution to this behavior somewhere but when I search with Google I get craploads of hits for jQuery Templates, which are different.

Does anyone have thoughts, answers or pointers to sites/pages that will help me through this? I'm trying to avoid cobbling together something hackish.

EDIT: I ended up finding this solution (I'm still testing it to make sure it IS a solution but it looks promising);

template = $("#some-id")
content = template.html()
new_div = $("<div></div>")
new_div.html(content)

I end up with that containing div that I didn't really need previously but I can live with that. But this kind of feels kludgy. Does anyone have a better approach to this? The upside is that it will still work in browsers that haven't adapted the template tag behavior fully yet.

thanks!

4

2 回答 2

23

尝试：

var myTemplate = $("#some-id").html().trim();
var myTemplateClone = $(myTemplate);
于 2013-11-24T18:58:43.250 回答
9

我相信这个站点将有助于解释 shadow dom 的工作原理以及模板如何与它们交互。 http://robdodson.me/blog/2013/08/27/shadow-dom-the-basics/

此外，克隆影子模板的节点实际上非常简单，甚至不需要使用 jquery。

这是一个演示它的 jfiddle：http: //jsfiddle.net/dtracers/fhWc3/1/

HTML：

<div id = "hoster">
    <span class = "title">Title</span>
    <span class = "id">51ab89af</span>
</div>

<template id = "im-a-template">
    <h1><content select =".title"></content></h1>
    <h1>Class Id: <content select = ".id"></content></h1>
    <input type="text" placeholder = "Name"></input>  
</template>

Javascript：

// find where you want to put your shadow dom in
var host = document.querySelector('#hoster');

var root = host.createShadowRoot(); // create the host root

var template = document.querySelector('#im-a-template');

// this is the node of the object you wanted
var documentFragment = template.content;

// this is a cloned version of the object that you can use anywhere.
var templateClone = documentFragment.cloneNode(true);

root.appendChild(templateClone); // this empty root now has your template
于 2014-04-15T01:30:33.083 回答