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我有一堆文件，想根据文件名中表示的日期对它们进行排序，如“2013-03-29_13-56-30”。我正在使用bash.

myapplication-1.0-SNAPSHOT-V2013-03-29_13-56-30.jar
myapplication-1.0-SNAPSHOT-V2013-12-03_17-01-51.jar
myapplication-1.0-SNAPSHOT-V2013-04-04_13-49-58.jar
myapplication-1.0-SNAPSHOT-V2013-04-04_14-25-51.jar
myapplication-1.0-SNAPSHOT-V2013-04-05_10-06-33.jar
myapplication-1.0-SNAPSHOT-V2013-04-05_13-49-49.jar
myapplication-1.0-SNAPSHOT-V2013-08-09_17-48-54.jar
myapplication-1.0-SNAPSHOT-V2013-11-10_09-46-33.jar

谢谢

我不确定，但sort -n似乎足够了，因为我所有文件中的前缀都相同。这个对吗？

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1 回答 1

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如果您已经在文件中有文件名，并且它们是无序的，那么sort在 fedorqui 的答案中使用 as 就可以了。但是，如果您在文件系统上有文件，那么您用来枚举它们的任何工具都会为您排序：

$ echo *
myapplication-1.0-SNAPSHOT-V2013-03-29_13-56-30.jar myapplication-1.0-SNAPSHOT-V2013-04-04_13-49-58.jar myapplication-1.0-SNAPSHOT-V2013-04-04_14-25-51.jar myapplication-1.0-SNAPSHOT-V2013-04-05_10-06-33.jar myapplication-1.0-SNAPSHOT-V2013-04-05_13-49-49.jar myapplication-1.0-SNAPSHOT-V2013-08-09_17-48-54.jar myapplication-1.0-SNAPSHOT-V2013-11-10_09-46-33.jar myapplication-1.0-SNAPSHOT-V2013-12-03_17-01-51.jar
$ ls
myapplication-1.0-SNAPSHOT-V2013-03-29_13-56-30.jar
myapplication-1.0-SNAPSHOT-V2013-04-04_13-49-58.jar
myapplication-1.0-SNAPSHOT-V2013-04-04_14-25-51.jar
myapplication-1.0-SNAPSHOT-V2013-04-05_10-06-33.jar
myapplication-1.0-SNAPSHOT-V2013-04-05_13-49-49.jar
myapplication-1.0-SNAPSHOT-V2013-08-09_17-48-54.jar
myapplication-1.0-SNAPSHOT-V2013-11-10_09-46-33.jar
myapplication-1.0-SNAPSHOT-V2013-12-03_17-01-51.jar

现在，可以影响这一点的一件事是LC_COLLATE环境变量。如果您不确定，请将其设置为C.

于 2013-04-10T11:20:02.150 回答