我有大约 100 行文本。每行具有以下格式:1 Gt 1.003
将Gt
更改,长度为 1 到 3 个字符。如何解析这一行并将 存储Gt
为字符串、存储1.003
为双精度并丢弃1
?
问问题
48 次
2 回答
1
很正常的东西。
ifstream file(...);
string line;
while (getline(file, line)
{
istringstream buf(line);
int dummy;
string tag;
double val;
buf >> dummy >> tag >> val;
}
tag
将是“Gt”,val
将是 1.003
于 2013-04-10T06:32:04.177 回答
1
using namespace std;
int discardInt;
string strInput;
double dblInput;
vector<string> strings;
vector<double> doubles;
ifstream infile("filename.txt"); //open your file
while(infile >> discard >> strInput >> dblInput) {
//now discard stores the value 1, which you don't use;
//strInput stores Gt or other 1-3 character long string;
//dblInput stores the double
//operations to store the values that are now in strInput and dblInput
//for example, to push the values into a vector:
strings.push_back(strInput);
doubles.push_back(dblInput);
}
infile.close();
于 2013-04-10T06:32:34.823 回答