0

晚上好，

我希望将通过 YQL 请求从 yahoo.finance.quote 获得的 JSON 块解析为要与 SQL DB 一起使用的列表。

这是相关的代码块：

String uri = "(\"GOOG\",\"YHOO\",\"AAPL\",\"C\",\"FB\",\"GE\",\"BAC\")";

String yql = "http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quote%20where%20symbol%20in%20" + uri + "&format=json&diagnostics=true&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys";  


        BufferedReader reader = null;
            URL url = new URL(yql);
            reader = new BufferedReader(new InputStreamReader(url.openStream()));

            Class1 data = gson.fromJson(reader, Class1.class);
            System.out.println(new Gson().toJson(data));

public class Class1 {
      private int query;
      private int results;
      private List<Class2> quote;
    }

    public class Class2 {
      private String Name;
    }

我想要从 JSON 获得的实际数据是 Data.Query.Result.Quote，但我似乎无法使用内部类（Class1、Class2）正确引用它。谁能提供一些帮助，或者让我知道我是否在做一些愚蠢的事情？谢谢你。

4

1 回答 1

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Query,results并且quote是JSONObjects 在他们自己的权利。您不能以这种方式映射它们并期望它能够工作。使用此结构作为参考并完成其余部分。

解析

Response fromJson = gson.fromJson(file, Response.class);
System.out.println(fromJson.getQuery().getResults().getQuote().getSymbol());

输出

谷歌

结构

public class Response
{
    private Query query;

    public Query getQuery()
    {
        return query;
    }

    public void setQuery(Query query)
    {
        this.query = query;
    }

}

class Query 
{
    private int count;
    private Results results;
    public int getCount()
    {
        return count;
    }
    public void setCount(int count)
    {
        this.count = count;
    }
    public Results getResults()
    {
        return results;
    }
    public void setResults(Results results)
    {
        this.results = results;
    }


}

class Results
{
    private Quote quote;

    public Quote getQuote()
    {
        return quote;
    }

    public void setQuote(Quote quote)
    {
        this.quote = quote;
    }


}

class Quote
{
    private String symbol;

    public String getSymbol()
    {
        return symbol;
    }

    public void setSymbol(String symbol)
    {
        this.symbol = symbol;
    }
}
于 2013-04-10T06:32:34.723 回答