0

我的脚本管理器的属性 enablepagemethods 设置为 true，但是，出于某种原因，这提醒我我失败了。

 public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }

    [WebMethod()]
    public static string test()
    {
        return "q343242342342";
    }
}

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
  function callMethod() {
      PageMethods.test(onSuccess, onFailure);
  }

  function onSuccess(result) {
      alert(result.d);
  }

  function onFailure(error) {
      alert('fail');
  } 
         </script>
 </head>
 <body>
 <form id="form1" runat="server">
 <asp:ScriptManager ID="ScriptManager1" runat="server"  EnablePageMethods="True">
 </asp:ScriptManager>
 <div>
    <asp:Button ID="Button1" OnClientClick="callMethod()" runat="server" Text="Button"/>
4

1 回答 1

1

这段代码对我有用 - 无法准确判断您的问题出在哪里，因为您在 runat=server 块中没有您的代码（假设您可能只是从后面的代码中复制）。但是这个确切的代码应该可以工作 - 我认为。

<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="Default.aspx.cs" Inherits="WebApplication1._Default" %>
<html>
<head runat="server">
<title>Sample Page</title>
<script runat="server">

    protected void Page_Load(object sender, EventArgs e)
    {

    }

    [System.Web.Services.WebMethod()]
    public static string test()
    {
        return "q343242342342";
    }

</script>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
  function callMethod() {
      PageMethods.test(onSuccess, onFailure);
  }

  function onSuccess(result) {
      alert(result);
  }

  function onFailure(error) {
      alert('fail');
  } 
         </script>
 </head>
 <body>
 <form id="form1" runat="server">
 <asp:ScriptManager ID="ScriptManager1" runat="server" EnablePageMethods="True">
 </asp:ScriptManager>
 <input type="button" id="btn" value="Click Me" onclick="callMethod();"  />
 </form>
 </body>
 </html>
于 2009-10-20T01:35:33.387 回答