3

我有一个实体类，看起来像这样。

@XmlRootElement
public class ImageSuffix {

    @XmlAttribute
    private boolean canRead;

    @XmlAttribute
    private boolean canWrite;

    @XmlValue;
    private String value;
}

我正在使用以下依赖项来生成 JSON。

<dependency>
  <groupId>com.fasterxml.jackson.jaxrs</groupId>
  <artifactId>jackson-jaxrs-json-provider</artifactId>
  <version>2.1.4</version>
</dependency>

当我尝试使用以下代码时，（参考Generating JSON Schemas with Jackson）

@Path("/imageSuffix.jsd")
public class ImageSuffixJsdResource {

    @GET
    @Produces({MediaType.APPLICATION_JSON})
    public String read() throws JsonMappingException {

        final ObjectMapper objectMapper = new ObjectMapper();

        final JsonSchema jsonSchema =
            objectMapper.generateJsonSchema(ImageSuffix.class);

        final String jsonSchemaString = jsonSchema.toString();

        return jsonSchemaString;
    }
}

服务器抱怨以下错误消息

java.lang.IllegalArgumentException: Class com.googlecode.jinahya.test.ImageSuffix would not be serialized as a JSON object and therefore has no schema
        at org.codehaus.jackson.map.ser.StdSerializerProvider.generateJsonSchema(StdSerializerProvider.java:299)
        at org.codehaus.jackson.map.ObjectMapper.generateJsonSchema(ObjectMapper.java:2527)
        at org.codehaus.jackson.map.ObjectMapper.generateJsonSchema(ObjectMapper.java:2513)

我怎样才能解决这个问题？

4

2 回答 2

6

您是否尝试过将 ObjectMapper 配置为包含 jaxb 内省器？我们使用 spring mvc3 来实现 REST 服务，并使用相同的模型对象序列化成 xml/json。

AnnotationIntrospector introspector = 
    new Pair(new JaxbAnnotationIntrospector(), new JacksonAnnotationIntrospector());
objectMapper.setAnnotationIntrospector(introspector);
objectMapper.generateJsonSchema(ImageSuffix.class);

编辑：这是我从杰克逊那里得到的输出：

{
  "type" : "object",
  "properties" : {
    "canRead" : {
      "type" : "boolean",
      "required" : true
    },
    "canWrite" : {
      "type" : "boolean",
      "required" : true
    },
    "value" : {
      "type" : "string"
    }
  }
}

希望这可以帮助！

于 2013-04-24T21:33:54.187 回答
0

提供的答案有点老了，现在有些东西已经被弃用了。Jackson因此，请使用最新和带JAXB/Moxy注释的类尝试以下代码：

方法一

class JsonSchemaGenerator{

  public static void main(String[] args) throws JsonProcessingException {
    ObjectMapper objectMapper = new ObjectMapper();
    TypeFactory typeFactory = TypeFactory.defaultInstance();
    AnnotationIntrospector introspector = new JaxbAnnotationIntrospector(typeFactory);
    objectMapper.getDeserializationConfig().with(introspector);
    objectMapper.getSerializationConfig().with(introspector);

    //To force mapper to include JAXB annotated properties in Json schema
    objectMapper.registerModule(new JaxbAnnotationModule());
    SchemaFactoryWrapper visitor = new SchemaFactoryWrapper();
    objectMapper.acceptJsonFormatVisitor(objectMapper.constructType(Customer.class), visitor);

    JsonSchema inputSchema = visitor.finalSchema();
    String schemaString = objectMapper.writerWithDefaultPrettyPrinter().writeValueAsString(inputSchema);

    System.out.println(schemaString);
  }

}

方法-2：

class JsonSchemaGenerator{
  public static void main(String[] args) throws JsonProcessingException, ClassNotFoundException {
    final ObjectMapper mapper = new ObjectMapper();
    final TypeFactory typeFactory = TypeFactory.defaultInstance();
    final AnnotationIntrospector introspector = new JaxbAnnotationIntrospector(typeFactory);
    mapper.getDeserializationConfig().with(introspector);
    mapper.getSerializationConfig().with(introspector);
    final JsonSchema jsonSchema = mapper.generateJsonSchema(Class.forName("com.jaxb.Customer"));
    System.out.println(jsonSchema);
  }
}
于 2021-06-02T15:20:14.670 回答