338

我有以下从外部方收到的 JSON 字符串。

{
   "team":[
      {
         "v1":"",
         "attributes":{
            "eighty_min_score":"",
            "home_or_away":"home",
            "score":"22",
            "team_id":"500"
         }
      },
      {
         "v1":"",
         "attributes":{
            "eighty_min_score":"",
            "home_or_away":"away",
            "score":"30",
            "team_id":"600"
         }
      }
   ]
}

我的映射类：

public class Attributes
{
    public string eighty_min_score { get; set; }
    public string home_or_away { get; set; }
    public string score { get; set; }
    public string team_id { get; set; }
}

public class Team
{
    public string v1 { get; set; }
    public Attributes attributes { get; set; }
}

public class RootObject
{
    public List<Team> team { get; set; }
}

问题是我不喜欢Attributes 类名和类中的字段attributes 名Team。相反，我希望它被命名TeamScore，并从字段名称中删除_并给出正确的名称。

JsonConvert.DeserializeObject<RootObject>(jsonText);

我可以重命名Attributes为TeamScore，但是如果我更改字段名称（attributes在Team类中），它将无法正确反序列化并给我null. 我该如何克服呢？

4

5 回答 5

673

Json.NET - Newtonsoft有一个JsonPropertyAttribute允许你指定 JSON 属性的名称，所以你的代码应该是：

public class TeamScore
{
    [JsonProperty("eighty_min_score")]
    public string EightyMinScore { get; set; }
    [JsonProperty("home_or_away")]
    public string HomeOrAway { get; set; }
    [JsonProperty("score ")]
    public string Score { get; set; }
    [JsonProperty("team_id")]
    public string TeamId { get; set; }
}

public class Team
{
    public string v1 { get; set; }
    [JsonProperty("attributes")]
    public TeamScore TeamScores { get; set; }
}

public class RootObject
{
    public List<Team> Team { get; set; }
}

文档：序列化属性

于 2013-04-10T02:55:50.737 回答
141

如果您想使用动态映射，并且不想用属性使模型混乱，这种方法对我有用

用法：

var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new CustomContractResolver();
this.DataContext = JsonConvert.DeserializeObject<CountResponse>(jsonString, settings);

逻辑：

public class CustomContractResolver : DefaultContractResolver
{
    private Dictionary<string, string> PropertyMappings { get; set; }

    public CustomContractResolver()
    {
        this.PropertyMappings = new Dictionary<string, string> 
        {
            {"Meta", "meta"},
            {"LastUpdated", "last_updated"},
            {"Disclaimer", "disclaimer"},
            {"License", "license"},
            {"CountResults", "results"},
            {"Term", "term"},
            {"Count", "count"},
        };
    }

    protected override string ResolvePropertyName(string propertyName)
    {
        string resolvedName = null;
        var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
        return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
    }
}
于 2015-07-17T20:54:52.010 回答
9

添加到 Jacks 解决方案。我需要使用 JsonProperty 和 Serialize 反序列化，同时忽略 JsonProperty（反之亦然）。ReflectionHelper 和 Attribute Helper 只是获取属性列表或属性的帮助器类。如果有人真正关心，我可以包括在内。使用下面的示例，即使 JsonProperty 是“RecurringPrice”，您也可以序列化视图模型并获得“Amount”。 

    /// <summary>
    /// Ignore the Json Property attribute. This is usefule when you want to serialize or deserialize differently and not 
    /// let the JsonProperty control everything.
    /// </summary>
    /// <typeparam name="T"></typeparam>
    public class IgnoreJsonPropertyResolver<T> : DefaultContractResolver
    {
        private Dictionary<string, string> PropertyMappings { get; set; }

        public IgnoreJsonPropertyResolver()
        {
            this.PropertyMappings = new Dictionary<string, string>();
            var properties = ReflectionHelper<T>.GetGetProperties(false)();
            foreach (var propertyInfo in properties)
            {
                var jsonProperty = AttributeHelper.GetAttribute<JsonPropertyAttribute>(propertyInfo);
                if (jsonProperty != null)
                {
                    PropertyMappings.Add(jsonProperty.PropertyName, propertyInfo.Name);
                }
            }
        }

        protected override string ResolvePropertyName(string propertyName)
        {
            string resolvedName = null;
            var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
            return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
        }
    }

用法：

        var settings = new JsonSerializerSettings();
        settings.DateFormatString = "YYYY-MM-DD";
        settings.ContractResolver = new IgnoreJsonPropertyResolver<PlanViewModel>();
        var model = new PlanViewModel() {Amount = 100};
        var strModel = JsonConvert.SerializeObject(model,settings);

模型：

public class PlanViewModel
{

    /// <summary>
    ///     The customer is charged an amount over an interval for the subscription.
    /// </summary>
    [JsonProperty(PropertyName = "RecurringPrice")]
    public double Amount { get; set; }

    /// <summary>
    ///     Indicates the number of intervals between each billing. If interval=2, the customer would be billed every two
    ///     months or years depending on the value for interval_unit.
    /// </summary>
    public int Interval { get; set; } = 1;

    /// <summary>
    ///     Number of free trial days that can be granted when a customer is subscribed to this plan.
    /// </summary>
    public int TrialPeriod { get; set; } = 30;

    /// <summary>
    /// This indicates a one-time fee charged upfront while creating a subscription for this plan.
    /// </summary>
    [JsonProperty(PropertyName = "SetupFee")]
    public double SetupAmount { get; set; } = 0;


    /// <summary>
    /// String representing the type id, usually a lookup value, for the record.
    /// </summary>
    [JsonProperty(PropertyName = "TypeId")]
    public string Type { get; set; }

    /// <summary>
    /// Billing Frequency
    /// </summary>
    [JsonProperty(PropertyName = "BillingFrequency")]
    public string Period { get; set; }


    /// <summary>
    /// String representing the type id, usually a lookup value, for the record.
    /// </summary>
    [JsonProperty(PropertyName = "PlanUseType")]
    public string Purpose { get; set; }
}
于 2015-09-24T16:06:35.207 回答
5

扩展Rentering.com 的答案，在需要处理多种类型的整个图表并且您正在寻找强类型解决方案的情况下，此类可以提供帮助，请参阅下面的用法（流畅）。它作为每种类型的黑名单或白名单运行。一个类型不能两者兼有（Gist - 还包含全局忽略列表）。

public class PropertyFilterResolver : DefaultContractResolver
{
  const string _Err = "A type can be either in the include list or the ignore list.";
  Dictionary<Type, IEnumerable<string>> _IgnorePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
  Dictionary<Type, IEnumerable<string>> _IncludePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
  public PropertyFilterResolver SetIgnoredProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
  {
    if (propertyAccessors == null) return this;

    if (_IncludePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);

    var properties = propertyAccessors.Select(GetPropertyName);
    _IgnorePropertiesMap[typeof(T)] = properties.ToArray();
    return this;
  }

  public PropertyFilterResolver SetIncludedProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
  {
    if (propertyAccessors == null)
      return this;

    if (_IgnorePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);

    var properties = propertyAccessors.Select(GetPropertyName);
    _IncludePropertiesMap[typeof(T)] = properties.ToArray();
    return this;
  }

  protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
  {
    var properties = base.CreateProperties(type, memberSerialization);

    var isIgnoreList = _IgnorePropertiesMap.TryGetValue(type, out IEnumerable<string> map);
    if (!isIgnoreList && !_IncludePropertiesMap.TryGetValue(type, out map))
      return properties;

    Func<JsonProperty, bool> predicate = jp => map.Contains(jp.PropertyName) == !isIgnoreList;
    return properties.Where(predicate).ToArray();
  }

  string GetPropertyName<TSource, TProperty>(
  Expression<Func<TSource, TProperty>> propertyLambda)
  {
    if (!(propertyLambda.Body is MemberExpression member))
      throw new ArgumentException($"Expression '{propertyLambda}' refers to a method, not a property.");

    if (!(member.Member is PropertyInfo propInfo))
      throw new ArgumentException($"Expression '{propertyLambda}' refers to a field, not a property.");

    var type = typeof(TSource);
    if (!type.GetTypeInfo().IsAssignableFrom(propInfo.DeclaringType.GetTypeInfo()))
      throw new ArgumentException($"Expresion '{propertyLambda}' refers to a property that is not from type '{type}'.");

    return propInfo.Name;
  }
}

用法：

var resolver = new PropertyFilterResolver()
  .SetIncludedProperties<User>(
    u => u.Id, 
    u => u.UnitId)
  .SetIgnoredProperties<Person>(
    r => r.Responders)
  .SetIncludedProperties<Blog>(
    b => b.Id)
  .Ignore(nameof(IChangeTracking.IsChanged)); //see gist
于 2017-05-12T02:38:12.017 回答
4

我在序列化时使用 JsonProperty 属性，但在使用以下反序列化时忽略它们ContractResolver：

public class IgnoreJsonPropertyContractResolver: DefaultContractResolver
    {
        protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
        {
            var properties = base.CreateProperties(type, memberSerialization);
            foreach (var p in properties) { p.PropertyName = p.UnderlyingName; }
            return properties;
        }
    }

只是将ContractResolver每个属性设置回类属性名称（从 Shimmy 的解决方案中简化）。用法：

var airplane= JsonConvert.DeserializeObject<Airplane>(json, 
    new JsonSerializerSettings { ContractResolver = new IgnoreJsonPropertyContractResolver() });
于 2020-05-04T13:12:01.627 回答