sql - What is the correct sql script for this select Statement?

Question

This is my script

SELECT iBranch_num,
   CASE WHEN iPatient_typ=1 THEN COUNT(iPatient_num) ELSE 0 END AS [New Patient], 
   CASE WHEN iPatient_typ=2 THEN COUNT(iPatient_num) ELSE 0 END AS [Buying Patient],                
   CASE WHEN iPatient_typ=3 THEN COUNT(iPatient_num) ELSE 0 END AS [Active Patient],
   CASE WHEN iPatient_typ=4 THEN COUNT(iPatient_num) ELSE 0 END AS [Inactive Patient]
FROM tblsotransaction
WHERE iStatus_typ=1
   AND iApply_dt BETWEEN 20130401 AND 20130408 
   AND iBranch_num=14
GROUP BY iBranch_num, iPatient_typ

Current Result:

14, 25, 0,  0,  0
14, 0,  8,  0,  0
14, 0,  0,  97, 0
14, 0,  0,  0,  2

I want the result to be like this

14, 25, 8,  9,  2

Answer 1

Wrap the whole CASE expression inside an aggregate function COUNT, and remove iPatient_typ from the GROUP BY clause:

SELECT 
  iBranch_num,
  COUNT(CASE WHEN iPatient_typ=1 THEN iPatient_num ELSE 0 END) AS [New Patient], 
  COUNT(CASE WHEN iPatient_typ=2 THEN iPatient_num ELSE 0 END) AS [Buying Patient],                
  COUNT(CASE WHEN iPatient_typ=3 THEN iPatient_num ELSE 0 END) AS [Active Patient],
  COUNT(CASE WHEN iPatient_typ=4 THEN iPatient_num ELSE 0 END) AS [Inactive Patient]
FROM tblsotransaction
WHERE iStatus_typ = 1 
  AND iApply_dt BETWEEN 20130401 AND 20130408 
  AND iBranch_num = 14
GROUP BY iBranch_num;

Or: SUM:

SELECT 
  iBranch_num,
  SUM(CASE WHEN iPatient_typ = 1 THEN 1 ELSE 0 END) AS [New Patient], 
  SUM(CASE WHEN iPatient_typ = 2 THEN 1 ELSE 0 END) AS [Buying Patient],
  SUM(CASE WHEN iPatient_typ = 3 THEN 1 ELSE 0 END) AS [Active Patient],
  SUM(CASE WHEN iPatient_typ = 4 THEN 1 ELSE 0 END) AS [Inactive Patient]
FROM tblsotransaction
WHERE iStatus_typ = 1 
  AND iApply_dt BETWEEN 20130401 AND 20130408 
  AND iBranch_num = 14
GROUP BY iBranch_num;