5

鉴于这样的事情..

 <?xml version="1.0" encoding="utf-8"?>
    <Project DefaultTargets="test" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
        <ItemGroup>
            <ConfigFiles Include="*.config" />

            <DatabaseConfig Include="ABC">
                <Database>DB1</Database>
                <CsString>Database</CsString>
            </DatabaseConfig>

            <DatabaseConfig Include="DEF">
                <Database>DB2</Database>
                <CsString>Logging</CsString>
            </DatabaseConfig>
        </ItemGroup>


        <Target Name="test" >
            <!-- Some sort of join here (or somewhere)... -->
         <Message Text=" %(Combined.ConfigFile) %(Combined.Database) " />
        </Target> 
    </Project>

我希望输出是这样的..(给定两个文件 one.config 和 two.config)

one.config DB1
two.config DB1
one.config DB2
two.config DB2

(顺序不重要,只是两个 ItemGroup 的全笛卡尔积)

4

2 回答 2

5

这似乎是一个整洁的解决方案:

<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="test" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
    <ItemGroup>
        <ConfigFiles Include="*.config" />

        <DatabaseConfig Include="ABC">
            <Database>DB1</Database>
            <CsString>Database</CsString>
        </DatabaseConfig>

        <DatabaseConfig Include="DEF">
            <Database>DB2</Database>
            <CsString>Logging</CsString>
        </DatabaseConfig>
    </ItemGroup>

    <Target Name="test" >
        <ItemGroup>
            <Combined Include="@(DatabaseConfig)">
                <ConfigFile>%(ConfigFiles.Identity)</ConfigFile>
            </Combined> 
        </ItemGroup>
    <Message Text=" %(Combined.ConfigFile) %(Combined.Database) " />
    </Target> 
</Project>
于 2013-04-10T14:36:30.563 回答
4

有一种方法可以通过对现有示例代码进行最少的更改来做到这一点。您可以将项目和项目中的元数据组合成一个新的“组合”项目,然后输出该“组合”项目。ConfigFilesDatabaseConfig

要组合元数据,请使用目标批处理DatabaseConfig和为每个项目运行一次的批处理目标。然后你可以调用另一个目标来输出组合的元数据以获得你描述的输出。看看我对您的示例代码的扩展,看看这一切是如何完成的:

<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="test" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">

  <ItemGroup>
    <ConfigFiles Include="*.config" />

    <DatabaseConfig Include="ABC">
      <Database>DB1</Database>
      <CsString>Database</CsString>
    </DatabaseConfig>

    <DatabaseConfig Include="DEF">
      <Database>DB2</Database>
      <CsString>Logging</CsString>
    </DatabaseConfig>
  </ItemGroup>

  <Target Name="test" DependsOnTargets="test_setup;test_output" >
    <!-- Logic here runs after targets listed in "DependsOnTargets". -->
  </Target>

  <!-- This will run once for each "DatabaseConfig" item. -->
  <Target Name="test_setup" Outputs="%(DatabaseConfig.Identity)">
    <PropertyGroup>
      <!-- Specify the Database for the current DatabaseConfig item -->
      <CurrentDb>%(DatabaseConfig.Database)</CurrentDb>
    </PropertyGroup>
    <ItemGroup>
      <!-- Add a new CombinedOutput item with each run, combining metadata. -->
      <CombinedOutput Include=" %(ConfigFiles.FileName)%(ConfigFiles.Extension) $(CurrentDb) " />
    </ItemGroup>
  </Target>

  <Target Name="test_output">
    <!-- Output the combined metadata from the CombinedOutput items -->
    <Message Text=" %(CombinedOutput.Identity) " />
  </Target>

</Project>

示例中发生了什么:

  1. test目标现在只是作为调用其他两个目标来执行工作的一种方式:test_setuptest_output
  2. test_setup目标被批处理并创建新 项目CombinedOutput
  3. test_output之后调用目标test_setup 以输出CombinedOutput项目的元数据。

输出test_output

one.config DB1
two.config DB1
one.config DB2
two.config DB2
于 2013-04-10T01:00:22.490 回答