android - Res->Raw，文件路径我使用“res/raw/filename.xml”但不起作用

Question

我有一个保存在 Res->Raw 中的 XML 文件，我想获取这个文件的路径，以便在函数的参数中传递它来解析它。

XML 文件的名称是family.xml，所以我尝试了这个但不起作用：“res/raw/families.xml”。有什么帮助吗？

Answer 1

Use :

 InputStream is=getResources().openRawResource(R.raw.families);

to get an InputStream to your XML, and then use XMLPullParser to parse the file :

 XmlPullParser xpp=XmlPullParserFactory.newInstance().newPullParser();
 xpp.setInput(is,"your-encoding");

Another alternative would be to put it in the assets folder.

Answer 2

res/ is just source folder. It does not exist in final app. If you want to retrieve your file you may want to either put it in assets folder or use getResources().openRawResource()