sql-server - 如何从存储过程启动 SQL Server 作业？

Question

如何创建存储过程来启动 SQL Server 作业？

Answer 1

-- Create SQL Server Agent job start stored procedure with input parameter
CREATE PROC uspStartMyJob @MyJobName sysname
AS
DECLARE @ReturnCode tinyint -- 0 (success) or 1 (failure)
EXEC @ReturnCode=msdb.dbo.sp_start_job @job_name=@MyJobName;
RETURN (@ReturnCode)
GO

或不带参数：

-- Create stored procedure to start SQL Server Agent job
CREATE PROC StartMyMonthlyInventoryJob
AS
EXEC msdb.dbo.sp_start_job N'Monthly Inventory Processing';
GO
-- Execute t-sql stored procedure
EXEC StartMyMonthlyInventoryJob

编辑仅供参考：如果您不想启动当前正在运行的作业，您可以在启动之前使用它，在您的存储过程中工作：

-- Get run status of a job
-- version for SQL Server 2008 T-SQL - Running = 1 = currently executing
 -- use YOUR guid here
DECLARE @job_id uniqueidentifier = '5d00732-69E0-2937-8238-40F54CF36BB1' 
EXEC master.dbo.xp_sqlagent_enum_jobs 1, sa, @job_id

Answer 2

您可以在存储过程中执行存储sp_start_job过程。

见这里：http: //msdn.microsoft.com/en-us/library/ms186757.aspx

Answer 3

创建您的存储过程并在您的 proc 中运行作业，如下所示：

DECLARE @JobId binary(16)
SELECT @JobId = job_id FROM msdb.dbo.sysjobs WHERE (name = 'JobName')

IF (@JobId IS NOT NULL)
BEGIN
    EXEC msdb.dbo.sp_start_job @job_id = @JobId;
END