2

我必须为这样的文本文件创建一个小程序：

hello_this_is_a_test_Example_
 this line has to go up because it has a space at the beginning
 this one too
this is the next line because there's no space at the start
 this one has to connect with the first line

我希望你明白。

所以最后，它应该将格式化的文本保存在这样的文件中：

hello_this_is_a_test_Example_ this line has to go up because it has a space at the beginning this one too
this is the next line because there's no space at the start this one has to connect with te upper again

基本上，如果该行在每个字符串的开头都有一个空格字符，则它必须与顶行连接。我已经有了 GUI 来选择这两个文件只需要算法。提前谢谢你：D

我现在有这个，但它把所有东西放在一条线上。这是不对的：

public class Engine {

    public void Process(String fileIn,String fileOut) throws IOException{
        System.out.println("[Info]--> Processign");
        System.out.println("[Info]--> FileIn = " + fileIn);
        System.out.println("[Info]--> FileOut = " + fileOut);
        FileWriter Writer = new FileWriter(fileOut);

        BufferedReader br = new BufferedReader(new FileReader(fileIn));
        String line;
        String modified;
        while ((line = br.readLine()) != null) {
         System.out.println(line);
            Writer.write(line);
         if(line.startsWith(" ")){
            modified = line.replaceAll("\n ", " ");
            Writer.write(modified);
         }
        } 
        br.close();
        Writer.close();}    
    }
4

1 回答 1

1

试试这个：

String modified = yourString.replaceAll("\n ", " ");

尝试这样的事情：

StringBuilder builder = new StringBuilder();
foreach (string line in Files.ReadAllLines(@"c:\myfile.txt"))
{
    builder.append(line);
}
String modified = builder.toString().replaceAll("\n ", " ");
FileWriter fw = new FileWriter(@"c:\myfile.txt");
fw.write(modified);
fw.close();
于 2013-04-09T11:47:05.300 回答