0

我想用 SQL 查询写一个 with in 。

去一些错误。请帮忙：

DECLARE @Start AS DATETIME;
DECLARE @End AS DATETIME;
SET @Start = '2013-04-09';
SET @End = '2013-04-11';
with View_Solidnet_Training as 
(
with View_Solidnet_Training as
(
select  cast(@Start as datetime) DateValue
union all
select DateValue + 1
from View_Solidnet_Training
where DateValue + 1 <= cast(@End as datetime)
)
insert into OBJ_Availability  
select 34, DateValue, 'AM', 2, 'Test' from View_Solidnet_Training;
)
select * from View_Solidnet_Training where PK_Training_ID is not null;

错误：

消息 156，级别 15，状态 1，第 7 行
关键字“with”附近的语法不正确。
消息 319，级别 15，状态 1，第 7 行
关键字“with”附近的语法不正确。如果此语句是公用表表达式或 xmlnamespaces 子句，则前面的语句必须以分号结束。
消息 102，级别 15，状态 1，第 17 行
')' 附近的语法不正确。

4

2 回答 2

1

尝试这个。这只是示例代码。在这段代码中，它是用 CTE 编写的 CTE。

;with CTE1 as (
SELECT Patientid
,Lastname1
,age
,dob
,ROW_NUMBER() OVER (ORDER BY Patientid DESC) AS RowNumber
FROM PTN_PATIENT    
)
,CTE2 AS (
SELECT CTE1.Patientid
,CTE1.Lastname1
,CTE1.age
,CTE1.dob
,CTE1.RowNumber
,DATEDIFF(YEAR,CTE1.dob,GETDATE()) as yearOfservce
FROM Lab_LabDiagOrder INNER JOIN CTE1
ON Lab_LabDiagOrder.Patientid = CTE1.Patientid
WHERE CTE1.RowNumber between 1 and 5
)
SELECT * FROM CTE2;
于 2013-04-09T09:40:45.270 回答
0

您不能在 CTE（公用表表达式）中拥有DECLARE和。SET

DECLARE @Start AS DATETIME;
DECLARE @End AS DATETIME;
SET @Start = '2013-04-09';
SET @End = '2013-04-11';

;WITH View_Solidnet_Training AS
(
    SELECT @Start AS DateValue

    UNION ALL

    SELECT DateValue + 1
    FROM View_Solidnet_Training
    WHERE DateValue + 1 <= @End 
)
SELECT
    34, DateValue, 'AM', 2, 'Test' 
FROM 
    View_Solidnet_Training
-- WHERE 
--    PK_Training_ID IS NOT NULL

我不知道它PK_Training_ID 应该来自哪里-在您的代码中找不到它.....

笔记：

  • 您不能在 CTE 中拥有DECLARE和SET- 只有SELECT和UNION ALL
  • @Startand@End已经被声明为- 再次将DATETIME它们强制转换为绝对没有意义DATETIME....
  • CTE 中的值在 CTE 之后立即可用，对于一个 T-SQL 语句
于 2013-04-09T09:27:44.307 回答