c# - 将 XML 文件转换为字符串类型

Question

我们如何将 XML 文件写入字符串变量？这是我的代码，变量内容应该返回一个 XML 字符串：

    public string GetValues2()
    {
        string content = "";
        XmlTextWriter textWriter = new XmlTextWriter(content, null);
        textWriter.WriteStartElement("Student");
        textWriter.WriteStartElement("r", "RECORD", "urn:record");
        textWriter.WriteStartElement("Name", "");
        textWriter.WriteString("Student");
        textWriter.WriteEndElement();
        textWriter.Close();

        return contents;

    }

Answer 1

像这样的东西

string xmlString =  System.IO.File.ReadAllText(fileName);

这是创建XmlDocument XDocument 或 XMLDocument的好答案

Answer 2

嗨Pedram你可以试试下面的代码

XmlDocument doc = new XmlDocument();

doc.LoadXml("yourXMLPath");
StringWriter sw = new StringWriter();
XmlTextWriter tx = new XmlTextWriter(sw);
doc.WriteTo(tx);
sw.ToString();

Answer 3

试试这个-

XmlDocument doc = new XmlDocument();
doc.LoadXml(your text string);

StringBuilder sb = new StringBuilder();
foreach (XmlNode node in doc.DocumentElement.ChildNodes)
{
    sb.Append(char.ToUpper(node.Name[0]));
    sb.Append(node.Name.Substring(1));
    sb.Append(' ');
    sb.AppendLine(node.InnerText);
}
return sb;

也看看这个-

    StringWriter sw = new StringWriter();
    XmlTextWriter tx = new XmlTextWriter(sw);
    myxml.WriteTo(tx);

    string str = sw.ToString();// 
    return str;

如果你真的想创建一个新的 XmlDocument 然后这样做

XmlDocument newxmlDoc= myxml

Answer 4

你可以试试：

static string GetXmlString(string strFile)
{
    // Load the xml file into XmlDocument object.
    XmlDocument xmlDoc = new XmlDocument();
    try
    {
        xmlDoc.Load(strFile);
    }
    catch (XmlException e)
    {
        Console.WriteLine(e.Message);
    }
    // Now create StringWriter object to get data from xml document.
    StringWriter sw = new StringWriter();
    XmlTextWriter xw = new XmlTextWriter(sw);
    xmlDoc.WriteTo(xw);
    return sw.ToString();
}

或者只是使用 XmlDocument.InnerXml 属性来获取 XML 字符串。

XmlDocument doc = new XmlDocument();
doc.Load("path to your file");
string xmlcontents = doc.InnerXml;