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#1064 - 您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，以在第 5 行的 '' 附近使用正确的语法

CREATE FUNCTION levenshtein( s1 VARCHAR(255), s2 VARCHAR(255) )  RETURNS INT  DETERMINISTIC  BEGIN    DECLARE s1_len , s2_len, i, j, c, c_temp, cost INT;    DECLARE s1_char CHAR;    -- max strlen=255    DECLARE cv0, cv1 VARBINARY(256);    SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = >0;    IF s1 = s2 THEN
     RETURN 0;    ELSEIF s1_len = 0 THEN
     RETURN s2_len;    ELSEIF s2_len = 0 THEN
     RETURN s1_len;    ELSE
     WHILE j <= s2_len DO
       SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1;
     END WHILE;
     WHILE i <= s1_len DO
       SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1;
       WHILE j <= s2_len DO
         SET c = c + 1;
         IF s1_char = SUBSTRING(s2, j, 1) THEN 
           SET cost = 0; ELSE SET cost = 1;
         END IF;
         SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost;
         IF c > c_temp THEN SET c = c_temp; END IF;
           SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1;
           IF c > c_temp THEN 
             SET c = c_temp; 
           END IF;
           SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1;
       END WHILE;
       SET cv1 = cv0, i = i + 1;
     END WHILE;    END IF;    RETURN c;  END;
4

2 回答 2

0

只是改变DELIMITER

DELIMITER $$
CREATE FUNCTION levenshtein(s1 VARCHAR(255), s2 VARCHAR(255))  
RETURNS INT
DETERMINISTIC
BEGIN
    DECLARE s1_len , s2_len, i, j, c, c_temp, cost INT;
    DECLARE s1_char CHAR;
    -- max strlen=255
    DECLARE cv0, cv1 VARBINARY(256);
    SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = 0;
    IF s1 = s2 THEN
        RETURN 0;
    ELSEIF s1_len = 0 THEN
        RETURN s2_len;
    ELSEIF s2_len = 0 THEN
        RETURN s1_len;
    ELSE
        WHILE j <= s2_len DO
            SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1;
        END WHILE;
        WHILE i <= s1_len DO
            SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1;
            WHILE j <= s2_len DO
                SET c = c + 1;
                IF s1_char = SUBSTRING(s2, j, 1) THEN 
                    SET cost = 0; 
                ELSE 
                    SET cost = 1;
                END IF;
                SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost;
                IF c > c_temp THEN 
                    SET c = c_temp; 
                END IF;
                SET c > c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1;
                IF c  c_temp THEN 
                  SET c = c_temp; 
                END IF;
                SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1;
            END WHILE;
            SET cv1 = cv0, i = i + 1;
        END WHILE;
    END IF;
RETURN c;
END $$
DELIMITER ;
于 2013-04-09T07:12:32.637 回答
0

在您的第 5 行中，使用 BEGINE 而不是 DO，在第 7 行中，使用 END 而不是 END WHILE

于 2013-04-09T07:22:23.420 回答