0

我正在获取并发布一些数据JSONParser.makeHttpRequest。当连接速度很慢时,需要一段时间才能得到响应,我想将超时限制设置为 5 秒。我发现这篇文章展示了如何设置 HttpResponse 超时,但无法将其与 JSONParser 集成。

这是我用于 HttpRequest 的代码

JSONParser jParser = new JSONParser();
List<NameValuePair> params = new ArrayList<NameValuePair>();
JSONObject json = jParser.makeHttpRequest(url, "GET", params);

如果我能在其他地方获得代码片段或另一个帖子的链接,我将不胜感激。

4

2 回答 2

2

这是代码:

public class JSONParser {

    static InputStream is = null;
    static JSONObject jObj = null;
    static String json = "";
    int timeout;

// constructor
public JSONParser() {
    timeout = new Values().gettimeout();
}

// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(String url, String method,
        List<NameValuePair> params) {

    // Making HTTP request
    try {
         HttpParams httpParameters = new BasicHttpParams();
         HttpConnectionParams.setSoTimeout(httpParameters, timeout);
        // check for request method
        if(method == "POST"){
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            HttpPost httpPost = new HttpPost(url);
            httpPost.setEntity(new UrlEncodedFormEntity(params));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }else if(method == "GET"){
            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            String paramString = URLEncodedUtils.format(params, "utf-8");
            url += "?" + paramString;
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();
        }           

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}
}

秘诀是:

     HttpParams httpParameters = new BasicHttpParams();
     HttpConnectionParams.setSoTimeout(httpParameters, timeout);

并将 de HttpParams 设置为

 DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);

调整你的代码来做到这一点;)

于 2013-09-20T23:03:46.600 回答
0

您可以使用 Asynctask,并在一段时间后停止请求。请参阅此处的示例。

于 2013-04-07T21:29:17.047 回答