mysql - SQL 查询 - 我的查询需要哪种 JOIN 类型？

Question

我有两个 sql 查询

第一个查询：我得到了除与日期相关的详细信息之外的所有详细信息

SELECT  att.roll_no  AS `att_roll_no`,att.full_name,att.st_class,att.st_section,
SUM(att.hasAttended= 'P') AS DaysPresent, 
SUM(att.hasAttended= 'A') AS DaysAbsent, 
COUNT(DISTINCT att.att_date) AS WorkingDays,
COUNT(*) AS totalClasses
FROM     attendance as att
WHERE att.st_class = 1 AND att.st_section = 'A' 
GROUP BY att.roll_no

上述查询的输出表如下：

第二个查询：我只得到与日期相关的详细信息

SELECT  hasAttended, att_date  FROM attendance
WHERE st_class = 1 AND st_section = 'A' AND att_date = 'Tue Apr 02 2013'
GROUP BY roll_no

上述查询的输出表如下：

现在我需要将上面的两个表连接到一个表中。

我尝试过的

在结果查询中，我使用的是 INNER JOIN。它如下：

SELECT
  att_outer.hasAttended,
  att_outer.att_date
FROM
  attendance AS att_outer
  INNER JOIN(
    SELECT 
      att.roll_no  AS `att_roll_no`,
      att.full_name,
      att.st_class,att.st_section,
      SUM(att.hasAttended= 'P') AS DaysPresent, 
      SUM(att.hasAttended= 'A') AS DaysAbsent, 
      COUNT(DISTINCT att.att_date) AS WorkingDays,
      COUNT(*) AS totalClasses
    FROM 
      attendance as att
    WHERE
      att.st_class = 1
      AND att.st_section = 'A' 
    GROUP BY att.roll_no
  )att ON att_outer.roll_no = att.roll_no
WHERE 
  att_outer.st_class = 1
  AND att_outer.st_section = 'A'
  AND att_outer.att_date = 'Tue Apr 02 2013'
GROUP BY roll_no

但我收到以下错误：

#1054 - Unknown column 'att.roll_no' in 'on clause'

请让我知道结果查询是否正确。另外加入我使用的是正确与否。

谢谢。

Answer 1

您想加入 ALIAS 名称，别名为att_roll_no

改变：

 ON att_outer.roll_no = att.roll_no

到

ON att_outer.roll_no = att_roll_no

Answer 2

您在 select 子句中没有名为 roll_no 的列，因此您无法对此进行连接，因此出现错误：att.roll_no。

Answer 3

您在内部查询中提供了该列的别名。您应该使用该别名，因为该列不再可见。

SELECT  att_outer.hasAttended, 
        att_outer.att_date,
        att.full_name,
        att.st_class,
        att.st_section,
        att.DaysPresent,
        att.DaysAbsent,
        att.WorkingDays,
        att.totalClasses
FROM    attendance AS att_outer
        INNER JOIN
        (
            SELECT  att.roll_no  AS `att_roll_no`,
                    att.full_name,
                    att.st_class,
                    att.st_section,
                    SUM(att.hasAttended= 'P') AS DaysPresent, 
                    SUM(att.hasAttended= 'A') AS DaysAbsent, 
                    COUNT(DISTINCT att.att_date) AS WorkingDays,
                    COUNT(*) AS totalClasses
            FROM    attendance as att
            WHERE   att.st_class = 1 AND 
                    att.st_section = 'A' 
            GROUP   BY att.roll_no
        )att ON att_outer.roll_no = att.att_roll_no
WHERE   att_outer.st_class = 1 AND 
        att_outer.st_section = 'A' AND 
        att_outer.att_date = 'Tue Apr 02 2013'