3

我不明白为什么这个 GROUP_CONCAT 不起作用，就外部查询而言，返回了 3 行，所以我想通过它来 group_concat 但它不喜欢它......

http://sqlfiddle.com/#!2/24764/3

CREATE TABLE nested_category (
        category_id INT AUTO_INCREMENT PRIMARY KEY,
        name VARCHAR(20) NOT NULL,
        lft INT NOT NULL,
        rgt INT NOT NULL
);

INSERT INTO nested_category VALUES(1,'ELECTRONICS',1,20),(2,'TELEVISIONS',2,9),(3,'TUBE',3,4),
 (4,'LCD',5,6),(5,'PLASMA',7,8),(6,'PORTABLE ELECTRONICS',10,19),(7,'MP3 PLAYERS',11,14),(8,'FLASH',12,13),
 (9,'CD PLAYERS',15,16),(10,'2 WAY RADIOS',17,18);

SELECT GROUP_CONCAT(rs.category_id, ',')
FROM 
    (
        SELECT node.category_id, node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
        FROM nested_category AS node,
                nested_category AS parent,
                nested_category AS sub_parent,
                (
                        SELECT node.category_id, node.name, (COUNT(parent.name) - 1) AS depth
                        FROM nested_category AS node,
                                nested_category AS parent
                        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                            AND node.name = 'PORTABLE ELECTRONICS'
                        GROUP BY node.name
                        ORDER BY node.lft
                )AS sub_tree
        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
                AND sub_parent.name = sub_tree.name
        GROUP BY node.name
        HAVING depth = 1
        ORDER BY node.lft
    ) as rs
GROUP BY rs.category_id
4

2 回答 2

9

两件事情：

第一：更改GROUP_CONCAT(rs.category_id, ',')为GROUP_CONCAT(rs.category_id)

逗号是默认分隔符，从文档中您可以看到，如果您想更改分隔符，则类似于 GROUP_CONCAT(rs.category_id SEPARATOR '|')

第二：删除最后一个： GROUP BY rs.category_id

如果你group byeach category_id，这意味着每个category_id都在它自己的集合中，这样group_concat每行只有一个类别。

http://sqlfiddle.com/#!2/24764/7

于 2013-04-07T06:20:29.940 回答
1

试试这个查询

SELECT GROUP_CONCAT(rs.category_id)
FROM 
    (
        SELECT node.category_id, node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
        FROM nested_category AS node,
                nested_category AS parent,
                nested_category AS sub_parent,
                (
                        SELECT node.category_id, node.name, (COUNT(parent.name) - 1) AS depth
                        FROM nested_category AS node,
                                nested_category AS parent
                        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                            AND node.name = 'PORTABLE ELECTRONICS'
                        GROUP BY node.name
                        ORDER BY node.lft
                )AS sub_tree
        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
                AND sub_parent.name = sub_tree.name
        GROUP BY node.name
        HAVING depth = 1
        ORDER BY node.lft
    ) as rs

输出

| GROUP_CONCAT(RS.CATEGORY_ID) |
--------------------------------
|                       7,9,10 |
于 2013-04-07T06:27:59.147 回答