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如何读取用户输入，一次一行来创建一个对象。然后哪个进入ArrayList？如您所见，当我输入名称时，它会将其分解并仅存储姓氏。或者如果我这样做：first-middle-last name，它存储中间名和姓氏。

我第一次输入名字，先调用search方法，看看这个名字是否已经存在于ArrayList中。这很好用。如果名称不在列表中，则搜索返回 null。然后提示输入和添加方法。

case 1: {
            System.out.print("Enter the Students name: ");
            String nameSearch = kbd.next();
            Student stu = dc.search(nameSearch );
            if (stu != null) {
                System.out.println(stu); 
            }
            else {
                System.out.print("Enter name AGAIN: ");
                String nameAdd= kbd.nextLine();

                System.out.print("Enter grade (freshman, sophomore, junior, senior: ");
                String categoryAdd = kbd.nextLine();

                System.out.print("Major: ");
                String majorAdd = kbd.nextLine();

                System.out.print("Enter graduating year: ");
                int yearAdd = kbd.nextInt();

                System.out.print("Enter student ID: (xxxx.xxxx: ");
                double idAdd= kbd.nextDouble();

                dc.add(nameAdd, categoryAdd , majorAdd , 
                        yearAdd , idAdd);
            }
            break;
        }

我的输入：

Enter the Students name: John Smith
Not Found(Search Method)
TEST
Enter name AGAIN: TEST2
Enter grade (freshman, sophomore, junior, senior: senior
Major: Computer Science
Enter graduating year: 2013
Enter student ID: 1234.4567

当我打印 ArrayList 时它是如何存储在对象中的：

Name: Smith
Grade: senior
Major: Computer Science
Graduating Year: 2013
Student ID: 1234.4567

添加方法：

public Student add(String name, String grade,
        String major, int year, double id) {
    Student newStu = new Student(addName, addGrade, addMajor, addYear, addId);
    studentList.add(newStu );
    System.out.println("Added!");
    return null;
}
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3 回答 3

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应该是String nameSearch = kbd.nextLine();。我阅读了多行java教程。希望这可以帮助。某种程度上来说。

于 2013-04-07T10:06:04.257 回答
0

这一行：

String nameSearch = kbd.next();

应该是

String nameSearch = kbd.nextLine();

正确的？

于 2013-04-07T06:05:58.977 回答
0

使kbd成为BufferedReader（例如BufferedReader kbd = new BufferedReader(new InputStreamReader(System.in));），然后执行此操作...

case 1: {
            System.out.print("Enter the Students name: ");
            String nameSearch = kbd.readLine();
            Student stu = dc.search(nameSearch );
            if (stu != null) {
                System.out.println(stu); 
            }
            else {
                System.out.print("Enter name AGAIN: ");
                String nameAdd= kbd.readLine();

                System.out.print("Enter grade (freshman, sophomore, junior, senior: ");
                String categoryAdd = kbd.readLine();

                System.out.print("Major: ");
                String majorAdd = kbd.readLine();

                System.out.print("Enter graduating year: ");
                int yearAdd = Integer.parseInt(kbd.readLine());

                System.out.print("Enter student ID: (xxxx.xxxx: ");
                double idAdd= Double.parseDouble(kbd.readLine());

                dc.add(nameAdd, categoryAdd , majorAdd , 
                        yearAdd , idAdd);
            }
            break;
        }
于 2013-04-07T07:08:21.820 回答