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我的直方图程序有问题，我正在让它打印出我想要的确切内容，但是它有一些不寻常的间距问题，我想知道是否有人可以帮助我避免它。这就是我的输出的样子，你可以看到它在 90-100 括号之前的所有空格中都有错误的间距。

在此处输入图像描述

我希望它看起来像这样，所以数字和星号之间的底部没有空格：

*
*
*   *
*   *
*   *
*   *
*   *
*   *
*   * *
* * * *
* * * *
0 1 2 3

也有人可以推荐一些东西来代替system("Clear")orsystem("PAUSE")吗？

代码：

#include <iostream>
#include <iomanip>

using namespace std;

void readExamMarks(int examMarks[], int sizeOfArray, int& counter1, int& counter2, int&   counter3, int& counter4,int& counter5, int& counter6,int& counter7, int& counter8, int& counter9, int& counter10){

cout << "Please enter a set of exam marks to see a histogram for:" << endl;
int x = 0;

for( int idx = 0; idx < sizeOfArray; idx++){
    cin >> x;
     if((x >=0) && (x <= 100)){
            x = x/10;

            switch(x){
            case 1:
                counter1++;

                break;
            case 2:
                counter2++;
                break;
            case 3:
                counter3++;

                break;
            case 4:
                counter4++;
                break;
            case 5:
                counter5++;

                break;
            case 6:
                counter6++;
                break;
            case 7:
                counter7++;

                break;
            case 8:
                counter8++;
                break;
            case 9:
                counter9++;

                break;
            case 10:
                counter9++;
                break;

            }

            examMarks[idx] = x;
        }
             else{
             cout << "ERROR: Value must be in range [0...100], please enter a valid value\n"; 
         }
}
}


void printExamMarksDecade(){

    cout << setw(5) << "10-20  " << "21-30  " << "31-40  " <<"41-50  " << "51-60  " << "61-70  " << "71-80  " << "81-90  " << "91-100  ";
}

void printHisto(int examMarks[], int sizeOfArray,int counter1, int counter2, int& counter3, int& counter4,int& counter5, int& counter6,int& counter7, int& counter8, int& counter9, int& counter10){
system("cls");

while(counter1 != 0 ){
    cout << setw(3) << "*" << endl;
    counter1--;
}
while(counter2 != 0 ){
    cout << setw(10) << "*" << endl;
    counter2--;
}
while(counter3 != 0 ){
    cout << setw(17) << "*" << endl;
    counter3--;
}
while(counter4 != 0 ){
    cout << setw(24) << "*" << endl;
    counter4--;
}
while(counter5 != 0 ){
    cout << setw(31) << "*" << endl;
    counter5--;
}
while(counter6 != 0 ){
    cout << setw(38) << "*" << endl;
    counter6--;
}
while(counter7 != 0 ){
    cout << setw(45) << "*" << endl;
    counter7--;
}
while(counter8 != 0 ){
    cout << setw(52) << "*" << endl;
    counter8--;
}
while(counter9 != 0 ){
    cout << setw(59) << "*" << endl;
    counter9--;
}
}

int main() 
{
int examMarks[30];
int counter1 = 0;
int counter2 = 0;
int counter3 = 0;
int counter4 = 0;
int counter5 = 0;
int counter6 = 0;
int counter7 = 0;
int counter8 = 0;
int counter9 = 0;
int counter10 = 0;

readExamMarks(examMarks, 30, counter1, counter2, counter3, counter4, counter5, counter6, counter7, counter8, counter9, counter10);
printHisto(examMarks, 30, counter1, counter2, counter3, counter4, counter5, counter6, counter7, counter8, counter9, counter10);
printExamMarksDecade();


system("PAUSE");
 }
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1 回答 1

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每个范围的变量counter并不是您真正想要做的，您只需要一个数组：

#include <iostream>
using namespace std;

int main() {

  // count array for brackets 0 to 10
  int *count = new int[11];
  // variable to store each mark read
  int mark;

  // Read in marks
  while (cin >> mark) {
    // Increment the count for the bracket the mark falls in 
    count[mark/10]++;
  }

  for (int i=0;i<11;i++) {
    cout << i << "\t| " << string(count[i],'*') << endl;
  }

}

这绘制了一个水平直方图，但显示了它应该完成的非常简单的方法。

$ ./histogram.out < marks
0   | ******
1   | *********
2   | **********
3   | ************
4   | *********
5   | *****************
6   | ********
7   | *********
8   | ***
9   | ****
10  | *

修改这段代码你会少一些麻烦，尝试将原始代码中的括号数增加到 1000！

于 2013-04-06T13:05:20.683 回答