javascript - 是否可以防止抛出特定的异常？

Question

有没有办法“白名单” - 或防止 - 在 try catch 块中抛出特定错误？

例如，假设我有一个我知道但不想记录的异常。但是，我想捕获该 try/catch 块中弹出的任何其他错误。

---

这是我能想到的最好的：

try {
...
} catch(exception) {

    //Loop through a predefined list of known errors that we want to ignore.
    for (var i in whitelistOfErrors) {

        //if our exception MATCHES an error that we want to ignore,
        //don't throw it
        if (exception == whitelistOfErrors[i])
            break;

        //if our exception DOESN'T MATCH an error that we want to ignore,
        //throw it
        if (i = whitelistOfErrors.length)
            throw exception;
    }
}

（或者用为您搜索数组的方法替换逻辑，如果存在的话）