0

这是我的代码。我对此非常陌生，不到 2 周，我知道这里某处存在语法错误，但它一直告诉我 T_variable 在第 12 行是意外的。它匹配“...input type="text" name=" firstname" value="First Name...\" 信息所以有人可以帮忙吗？Noob 需要帮助！只是一点点...？你能告诉我的任何事情都会非常感激。

<?
$correct = true;
if ($_GET["name"] == "")
    $correct = false;
if (preg_match("/^.+@\w+\.\w{2,4}$/", $_GET["email"]))
    $correct = false;

$to = "sample@domain.com";
$subject = "Application request";

$message = "A new request has come in!;\n\n"
$message .= $_GET["firstname"].;
$message .= $_GET["lastname"].;

$message .= $_GET["email"]."\n";

$message .= $_GET["phone"]."\n";
$message .= $_GET["dropdown"]."\n";
$message .= $_GET["address"]."\n";
$message .= $_GET["dropdown2"]."\n";
$message .= $_GET["textarea"]."\n";


(mail($to, $subject, $message);

?>

<body>
<? if ($correct): ?>
Thank you for applying. We will get back to you shortly.<br>
<? if else: ?>
Please complete the form.
</ end if ?>




</body>
4

3 回答 3

1

几个问题：

1

$message = "A new request has come in!;\n\n"

应该变成：

$message = "A new request has come in!;\n\n";

2.

$message .= $_GET["firstname"].;

应该变成：

$message .= $_GET["firstname"];
于 2013-04-05T15:41:14.810 回答
1

半冒号在错误的地方

$message = "A new request has come in!;\n\n"
                                      ^

应该：

$message = "A new request has come in!\n\n";
                                           ^

你也有错误的时期：

$message .= $_GET["firstname"].;
$message .= $_GET["lastname"].;
                             ^
于 2013-04-05T15:41:16.353 回答
0 
$message .= $_GET["firstname"].;
                              ^ Remove
$message .= $_GET["lastname"].;
                             ^ Remove

$message = "A new request has come in!;\n\n"
                                            ^ -> semicolon here 
(mail($to, $subject, $message);
^ -> remove this
于 2013-04-05T15:48:57.863 回答