1

我正在制作一个应用程序，但我遇到了问题。当我点击按钮时，我需要在我的画布上添加新点（图像）。这是一个代码：

var ID = 0;
var points = [];

function addPoint(){
points.push({id: ID, posX: 0, posY: 0, url: "img/point.png"});
ID++;
showPoints();
}

function showPoints(){
var img = new Array();
var point = new Array();
var stage = new Kinetic.Stage({
    container: 'cvsCroatia',
    width: 574,
    height: 508
});
var layer = new Kinetic.Layer();

for(var j=0; j < ID; j++){
    img[j] = new Image();
    img[j].src = 'img/point.png';
    img[j].onload = (function(){
        point[j] = new Kinetic.Image({
            x: points[j].posX,
            y: points[j].posY,
            image: img[j],
            width: 13,
            height: 13,
            name:  img[j],
            draggable: true
        });
    });
    layer.add(point[j]);

}   
stage.add(layer);
}

但我得到一个错误：

未捕获的类型错误：无法设置未定义的属性“索引”（动力学-v4.4.0.min.js:29）

你有什么想法，有什么问题吗？谢谢回答。艾伦..

4

2 回答 2

0 
var img = new Array(); // the simplest solution is to make img visible outside your function
function showPoints(){
    // var img = new Array();        // HERE img is a LOCAL variable, only visible to the showPoints() function
    var point = new Array();        
    var stage = new Kinetic.Stage({
    container: 'cvsCroatia',
    width: 574,
    height: 508
});
于 2013-04-05T13:20:45.010 回答
0

感谢您的回答，我将所有变量都放到了全局范围内，但不幸的是得到了同样的错误..

 var ID = 0;
 var points = [];

 var img = new Array();
 var point = new Array();

 function showPoints(){
var stage = new Kinetic.Stage({
    container: 'cvsCroatia',
    width: 574,
    height: 508
});
var layer = new Kinetic.Layer();

for(var j=0; j < ID; j++){
    img[j] = new Image();
    img[j].src = 'img/point.png';
    img[j].onload = (function(){
        point[j] = new Kinetic.Image({
            x: points[j].posX,
            y: points[j].posY,
            image: img[j],
            width: 13,
            height: 13,
            name:  img[j],
            draggable: true
        });
    });
    layer.add(point[j]);

}   
stage.add(layer);
 }

  function addPoint(){
points.push({id: ID, posX: 0, posY: 0, url: "img/point.png"});
ID++;
showPoints();
}
于 2013-04-13T07:48:04.980 回答