3

我正在尝试为我的表获取行号。到目前为止，这是我的 SQL 提示：

SELECT @i = @i + 1 AS Rank, x.Name, x.PartyName, x.ConstituencyName, x.Votes 
FROM (
    SELECT CONCAT(t1.Firstname, ' ', t1.Lastname) AS Name, t1.PartyName, t1.ConstituencyName, COALESCE(t2.Count, 0) AS Votes
        FROM (
            (SELECT db.user.PID, db.user.Firstname, db.user.Lastname, db.party.PartyName, db.constituency.ConstituencyName 
                FROM db.user
                LEFT JOIN db.party ON db.user.PartyId = db.party.PartyID 
                LEFT JOIN db.constituency ON db.user.CID = db.constituency.CID
                WHERE db.user.PartyId IS NOT NULL
                AND db.user.CID IS NOT NULL
            ) t1
            LEFT JOIN
            (SELECT db.user.Vote, COUNT(*) AS 'Count' 
                FROM db.user 
                GROUP BY db.user.Vote
            ) t2
        ON
            t1.PID = t2.Vote
        ORDER BY t2.Count DESC)
        ) x,
(SELECT @i:=1) r

所以这基本上做的是，首先我创建一个表 t1（从 2 个不同的表中获取信息），然后将它与表 t2 连接起来，这样我就可以得到每个候选人的总票数。然后我将该表标记为“x”并将其与应该初始化行号的表“r”连接（使用行号的在线教程）。但是，当我运行此 SQL 提示时，我得到以下回报：

Rank    Name    PartyName   ConstituencyName    Votes
0       Name1   Party1      Constituency1       700
0       Name2   Party1      Constituency1       550

任何建议将不胜感激。

4

1 回答 1

3

这是用户变量，您不应该:=使用=

SELECT @i := @i + 1 AS Rank,...
于 2013-04-04T23:19:00.650 回答