如何在不更改工作目录的情况下使用 JGit 获取分支的所有提交?
不幸的是,JGit 文档不是很好......
在带有砂砾的红宝石中,这很容易:
repo = Grit::Repo.new(pathToRepo)
repo.commits(branchName, false).each do |commit|
doSomethingWithTheCommit
end
再见,胡里克
首先在这里尝试:https ://stackoverflow.com/a/13925765/2246865
但它并不总是有效,所以我在这里找到了这个:http: //www.eclipse.org/forums/index.php/t/280339/
这是我的解决方案,它不是很好,但它正在工作......
public static void main(String[] args) throws IOException, GitAPIException {
Repository repo = new FileRepository("pathToRepo/.git");
Git git = new Git(repo);
RevWalk walk = new RevWalk(repo);
List<Ref> branches = git.branchList().call();
for (Ref branch : branches) {
String branchName = branch.getName();
System.out.println("Commits of branch: " + branch.getName());
System.out.println("-------------------------------------");
Iterable<RevCommit> commits = git.log().all().call();
for (RevCommit commit : commits) {
boolean foundInThisBranch = false;
RevCommit targetCommit = walk.parseCommit(repo.resolve(
commit.getName()));
for (Map.Entry<String, Ref> e : repo.getAllRefs().entrySet()) {
if (e.getKey().startsWith(Constants.R_HEADS)) {
if (walk.isMergedInto(targetCommit, walk.parseCommit(
e.getValue().getObjectId()))) {
String foundInBranch = e.getValue().getName();
if (branchName.equals(foundInBranch)) {
foundInThisBranch = true;
break;
}
}
}
}
if (foundInThisBranch) {
System.out.println(commit.getName());
System.out.println(commit.getAuthorIdent().getName());
System.out.println(new Date(commit.getCommitTime() * 1000L));
System.out.println(commit.getFullMessage());
}
}
}
}
使用下面的代码,您可以获得分支或标签的所有提交:
Repository repository = new FileRepository("/path/to/repository/.git");
String treeName = "refs/heads/master"; // tag or branch
for (RevCommit commit : git.log().add(repository.resolve(treeName)).call()) {
System.out.println(commit.getName());
}
变量treeName
将定义标签或分支。这是分支或标签的treeName
完整名称,例如master分支或名为v1.0的标签。refs/heads/master
refs/tags/v1.0
或者,您可以使用gitective API。以下代码与上面的代码相同:
Repository repository = new FileRepository("/path/to/repository/.git");
AndCommitFilter filters = new AndCommitFilter();
CommitListFilter revCommits = new CommitListFilter();
filters.add(revCommits);
CommitFinder finder = new CommitFinder(repository);
finder.setFilter(filters);
String treeName = "refs/heads/master"; // tag or branch
finder.findFrom(treeName);
for (RevCommit commit : revCommits) {
System.out.println(commit.getName());
}
一些 try/catch 将是必要的,我隐藏它们以使代码更短。祝你好运。
我只是在寻找一种方法来列出每个分支下的所有提交,我发现了这个线程。我终于做了一些与我在这里找到并工作的一些答案有点不同的事情。
public static void main(String[] args) throws IOException, GitAPIException {
Repository repo = new FileRepository("pathToRepo/.git");
Git git = new Git(repo);
List<Ref> branches = git.branchList().call();
for (Ref branch : branches) {
String branchName = branch.getName();
System.out.println("Commits of branch: " + branchName);
System.out.println("-------------------------------------");
Iterable<RevCommit> commits = git.log().add(repo.resolve(branchName)).call();
List<RevCommit> commitsList = Lists.newArrayList(commits.iterator());
for (RevCommit commit : commitsList) {
System.out.println(commit.getName());
System.out.println(commit.getAuthorIdent().getName());
System.out.println(new Date(commit.getCommitTime() * 1000L));
System.out.println(commit.getFullMessage());
}
}
git.close();
}
谢谢您的帮助
你是对的,文档应该真的更好。
您可以使用JGit Log 命令或使用像gitective这样的库,这使得迭代提交变得容易。您可以查看源代码以了解有关 JGit 的更多信息。
此 SO-question中描述了其他(更复杂的)方法。
可以通过 JGit 提供的“log”命令来完成更短更干净的解决方案:
Repository repository = new FileRepository("pathToRepo/.git");
logs = new Git(repository).log()
.add(repository.resolve("remotes/origin/testbranch"))
.call();
count = 0;
for (RevCommit rev : logs) {
System.out.println("Commit: " + rev /* + ", name: " + rev.getName() + ", id: " + rev.getId().getName() */);
count++;
}
System.out.println("Had " + count + " commits overall on test-branch");
请参阅jgit-cookbook中的完整片段
这似乎可行,但我认为 add(ObjectId branch) 为活动分支提供了一个大门,但我似乎需要一个范围
Git git = ...
ObjectId master = git.repository.resolve("refs/heads/master")
ObjectId branch = git.repository.resolve("refs/heads/mybranch")
git.log().addRange(master,branch).call()