我是春天的新手。我正在尝试将 Spring 集成到 Web 应用程序的一部分中。它必须与以下网址一起使用：
http://localhost:9080/myfolder/myspring
我的web.xml包括：
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/config/myspring-context.xml
</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/config/applicationContext.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/springviews</url-pattern>
</servlet-mapping>
应用上下文.xml：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:aop="http://www.springframework.org/schema/aop"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<!-- registers all of Spring's standard post-processors for annotation-based configuration -->
<context:annotation-config />
<tx:annotation-driven/>
<tx:jta-transaction-manager/>
<bean id="properties" class="springcop.pojo.TestObject">
</bean>
</beans>
我的myspring-context.xml是：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Scans within the base package of the application for @Components to configure as beans -->
<!-- @Controller, @Service, @Configuration, etc. -->
<context:component-scan base-package="springcop"/>
<!-- Configures the @Controller programming model -->
<mvc:annotation-driven/>
<!-- Resolve logical view names to .jsp resources in the /WEB-INF/views directory -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/springviews/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
这是MyController
package springcop;
import java.util.Map;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
public class MyController {
public MyController () {
System.out.println("--->GestioneController");
}
@RequestMapping(value = "/test", method = RequestMethod.GET)
public String test() {
System.out.println("--->test");
return "test";
}
}
up运行没有错误。正如我在我的日志中打印的那样，Spring 似乎可以工作“--->GestioneController，它位于我的 COntroller 的构造函数中。
无论如何，当我在浏览器中打开
http://localhost:9080/myfolder/myspring/test
在 MyController 中执行测试方法我得到 404 错误。
我应该怎么做才能让它工作？谢谢。