我是 Android 编程新手，我需要实现一个 Android resteasy-mobile 客户端。我需要连接远程 JAX-RS Web 服务。我正在搜索周围，但找不到简单的示例客户端。你能告诉我如何制作一个 Android resteasy-mobile 客户端吗？
先感谢您。
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1 回答
1
最后，我决定使用 Jersey 服务器实现一个 Android json (Jackson) 客户端。如果有人需要知道它是怎么回事，这是我的代码：
服务器：
package com.sl;
import javax.ws.rs.Consumes;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import com.sl.model.pojo.UserLocation;
@Path("/json/service")
public class JSONService {
@GET
@Path("/get")
@Produces(MediaType.APPLICATION_JSON)
public UserLocation getTrackInJSON() {
UserLocation ul = new UserLocation();
ul.setCodigo("1");
ul.setLatitud(Float.valueOf("1.1"));
ul.setLongitud(Float.valueOf("1.2"));
return ul;
}
@POST
@Path("/post")
@Consumes(MediaType.APPLICATION_JSON)
public Response createTrackInJSON(UserLocation userLocation) {
String result = "Record saved.";
return Response.status(201).entity(result).build();
}
}
web.xml
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Restful Web Application</display-name>
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.resourceConfigClass</param-name>
<param-value>com.sun.jersey.api.core.PackagesResourceConfig</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.sl</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
客户：
ReceiveFeedTask.java
package android.jaxrs;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.codehaus.jackson.map.ObjectMapper;
import android.jaxrs.model.pojo.UserLocation;
import android.os.AsyncTask;
import android.util.Log;
public class RetreiveFeedTask extends AsyncTask<String, String, Boolean> {
private static String TAG = "ReceiveFeedTask";
private String jaxrsmessage = null;
private static String IP = "191.162.1.107"; //IP CASA
//private static String IP = "10.0.2.2"; //IP LOCALHOST
private static String DIRECCION_GET = "http://" + IP + ":8080/ServidorLoc/rest/json/service/get";
private static String DIRECCION_POST = "http://" + IP + ":8080/ServidorLoc/rest/json/service/post";
private final ObjectMapper mapper = new ObjectMapper();
@Override
protected Boolean doInBackground(String... params) {
HttpClient httpclient = null;
try {
android.os.Debug.waitForDebugger();
httpclient = new DefaultHttpClient();
HttpGet request = new HttpGet(DIRECCION_GET);
request.addHeader("Content-Type", "application/json");
request.addHeader("Accept", "application/json");
HttpResponse response = httpclient.execute(request);
HttpEntity entity = response.getEntity();
InputStream instream = entity.getContent();
jaxrsmessage = read(instream);
Log.d(TAG, jaxrsmessage);
//POST
UserLocation ul= new UserLocation();
ul.setCodigo("2");
ul.setLatitud(Float.valueOf("2.1"));
ul.setLongitud(Float.valueOf("2.2"));
String json = mapper.writeValueAsString(ul);
HttpPost post = new HttpPost(DIRECCION_POST);
post.setHeader("Content-Type", "application/json");
StringEntity se = new StringEntity(json);
post.setEntity(se);
HttpResponse httpResponse = new DefaultHttpClient().execute(post);
String retSrc = EntityUtils.toString(httpResponse.getEntity());
Log.d(TAG, retSrc);
} catch (ClientProtocolException e) {
Log.e(TAG, "Se ha producido un error: " + e.toString() + "\nMensaje: " + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "Se ha producido un error: " + e.toString() + "\nMensaje: " + e.getMessage());
} catch (Exception e){
Log.e(TAG, "Se ha producido un error: " + e.toString() + "\nMensaje: " + e.getMessage());
}finally {
httpclient.getConnectionManager().shutdown();
}
return true;
}
@Override
protected void onPostExecute(Boolean result) {
}
private static String read(InputStream instream) {
StringBuilder sb = null;
try {
sb = new StringBuilder();
BufferedReader r = new BufferedReader(new InputStreamReader(
instream));
for (String line = r.readLine(); line != null; line = r.readLine()) {
sb.append(line);
}
instream.close();
r.close();
} catch (IOException e) {
Log.e(TAG, "Se ha producido un error: " + e.toString() + "\nMensaje: " + e.getMessage());
}
return sb.toString();
}
}
AndroidManifest.xml
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="android.jaxrs"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="16" />
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
<application
android:icon="@drawable/ic_launcher"
android:label="@string/app_name">
<activity
android:name="android.jaxrs.AndroidJAXRSClient"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
就这样！！！:)
于 2013-04-06T09:58:43.107 回答