xml - 如何使用 XSLT 将 XML 文件的节点更改为另一个 XML 文件中的节点？

Question

一个 XML 文件有

<x1>
<x2>xyz</x2>
<x3>xy</x3>
<x4>z</x4>
<x5>123</x5>
</x1>

另一个 XML 有

<?xml version="1.0" standalone="yes"?>
<DocumentElement>
  <c>
    <ID>1</ID>
    <XMLFieldName>UserDetails</XMLFieldName>
  </c>
  <c>
    <ID>2</ID>
    <XMLFieldName>UserName</XMLFieldName>
  </c>
  <c>
    <ID>3</ID>
    <XMLFieldName>FirstName</XMLFieldName>
  </c>
  <c>
    <ID>4</ID>
    <XMLFieldName>LastName</XMLFieldName>
  </c>
  <c>
    <ID>5</ID>
    <XMLFieldName>EmployeeID</XMLFieldName>
  </c>
</DocumentElement>

我想得到结果 XML

<UserDetails>
<UserName>xyz</UserName>
<FirstName>xy</FirstName>
<LastName>z</LastName>
<EmployeeID>123</EmployeeID>
</UserDetails>

更多信息：实际上第一个和第二个文件在 DB 表中作为 XML 数据类型。我只需要一个 XSLT 来获取第三个 XML 和 X1,x2.... 节点基于标签 ID。

提前谢谢..:-)

Answer 1

这是一个与 XSLT 1.0 兼容的选项：

样式表

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>

  <!--
  Pass the name of the other XML file as a parameter to the transformation;
  x1.xml is used by default
  -->
  <xsl:param name="x1" select="'x1.xml'"/>

  <xsl:template match="/">
    <!-- Only apply the first <c> element -->
    <xsl:apply-templates
      select="DocumentElement/c[XMLFieldName = 'UserDetails']"/>
  </xsl:template>

  <xsl:template match="c[XMLFieldName = 'UserDetails']">
    <!-- Use the value of the XMLFieldName element as the element name -->
    <xsl:element name="{XMLFieldName}">
      <!-- Apply following <c> siblings -->
      <xsl:apply-templates select="following-sibling::c"/>
    </xsl:element>
  </xsl:template>

  <xsl:template match="c">
    <!-- Save the value of the ID child of current <c> element -->
    <xsl:variable name="id" select="ID"/>

    <xsl:element name="{XMLFieldName}">
      <!--
      Get the value of the element in x1.xml that has the same number in its
      element name as the value of the <ID> child of this <c> element
      -->
      <xsl:value-of
        select="document($x1)/*/*[substring-after(local-name(), 'x') = $id]"/>
    </xsl:element>
  </xsl:template>

</xsl:stylesheet>

输入

<?xml version="1.0" standalone="yes"?>
<DocumentElement>
  <c>
    <ID>1</ID>
    <XMLFieldName>UserDetails</XMLFieldName>
  </c>
  <c>
    <ID>2</ID>
    <XMLFieldName>UserName</XMLFieldName>
  </c>
  <c>
    <ID>3</ID>
    <XMLFieldName>FirstName</XMLFieldName>
  </c>
  <c>
    <ID>4</ID>
    <XMLFieldName>LastName</XMLFieldName>
  </c>
  <c>
    <ID>5</ID>
    <XMLFieldName>EmployeeID</XMLFieldName>
  </c>
</DocumentElement>

x1.xml

<x1>
  <x2>xyz</x2>
  <x3>xy</x3>
  <x4>z</x4>
  <x5>123</x5>
</x1>

输出

<?xml version="1.0" encoding="utf-8"?>
<UserDetails>
  <UserName>xyz</UserName>
  <FirstName>xy</FirstName>
  <LastName>z</LastName>
  <EmployeeID>123</EmployeeID>
</UserDetails>