2

我正在尝试创建一个带有彩色方块的选项组，供用户选择。它在 3.2 设备上运行，如下图所示： 在此处输入图像描述

代码类似于：

for (int i = 0; i < COLORS.length; i++) {
        CheckBox box = new CheckBox(context);
        box.setBackgroundDrawable(getColorOption(context, COLORS[i]));
        box.setButtonDrawable(android.R.color.transparent);

然后，在 getColorOption 函数中，我创建了 StateListDrawable：

    StateListDrawable slDrawable = new StateListDrawable();

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] {
            new SelectFrameShapeDrawable(transparentColor, lightRedColor),
            new SquareShapeDrawable(color) });
    LayerDrawable uncheckedDrawable = new LayerDrawable(new Drawable[] {
                    new SelectFrameShapeDrawable(transparentColor, transparentColor),
                    new SquareShapeDrawable(color) });
    slDrawable.addState(new int[] { android.R.attr.state_checked },
            checkedDrawable);
    slDrawable.addState(new int[] { -android.R.attr.state_checked }, uncheckedDrawable);
    return slDrawable;

SquareShapeDrawable 类是一个 ShapeDrawable：

public class SquareShapeDrawable extends ShapeDrawable {
    private final Paint fillpaint;

    public SquareShapeDrawable(int color) {
        super(new RectShape());
        fillpaint = new Paint(this.getPaint());
        fillpaint.setColor(color);
    }

    @Override
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) {
        shape.draw(canvas, fillpaint);
    }
}

SelectFrameShapeDrawable 是：

private class SelectFrameShapeDrawable extends ShapeDrawable {
private final Paint fillpaint, strokepaint;

public SelectFrameShapeDrawable(int fill, int stroke) {
        super(new RectShape());
        strokepaint = new Paint(this.getPaint());
        strokepaint.setStyle(Paint.Style.STROKE);

        strokepaint.setStrokeWidth((int) (getResources()
                .getDisplayMetrics().density + 0.5f));
        strokepaint.setColor(stroke);
        int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f);
        setPadding(padding, padding, padding, padding);

        fillpaint = new Paint(strokepaint);
        fillpaint.setColor(fill);
    }

    @Override
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) {
        if (strokepaint != null)
            shape.draw(canvas, strokepaint);
        shape.draw(canvas, fillpaint);
    }
}

在 4.2 设备上，所有方块都是黑色的，并且在选中时不会改变： 在此处输入图像描述

问题似乎是在将可绘制对象添加到 StateListDrawable 时......知道如何解决这个问题吗？

4

2 回答 2

1

我通过删除扩展 ShapeDrawable 的自定义类并用下面直接使用 ShapeDrawable 类的代码替换它们来解决黑色方块问题。此代码似乎适用于所有平台。

奇怪的是，原始问题出现在 4.2 而不是 3.2。我最初的灵感来源是：http ://www.betaful.com/2012/01/programmatic-shapes-in-android/

    ShapeDrawable selectFrame = new ShapeDrawable();
    selectFrame.setShape(new RectShape());
    selectFrame.getPaint().setColor(lightRedColor);
    selectFrame.getPaint().setStyle(Paint.Style.STROKE);
    selectFrame.getPaint().setStrokeWidth((int) (getResources().getDisplayMetrics().density + 0.5f));
    int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f);
    selectFrame.setPadding(padding, padding, padding, padding);

    ShapeDrawable square = new ShapeDrawable();
    square.setShape(new RectShape());
    square.getPaint().setColor(color);

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] {
            selectFrame, square });
...
于 2013-05-04T19:50:34.673 回答
0

在我的带有 android 4.2 修订版 2（最新更新）的模拟器中，复选框没有出现，我发现问题是：当 setButtonDrawable 为 null 或 ColorDrawable 时，复选框测量它的大小为 0 的宽度。这不是 StateListDrawable 的原因。

我尝试设置复选框的宽度和高度，一切似乎都很好。试试这个：box.setWidth(30); box.setHeight(30); 或者当您使用“new RelativeLayout.LayoutParams(50, 50));”之类的布局参数将复选框添加到布局时。希望这有帮助

于 2013-04-06T04:29:29.173 回答