我想在我的 Android 应用程序中有两件事。
获取设备 id,然后使用此 id 打开网页。例如myserver.com/deviceId
我的主要 java 类如下所示:
package es.unican.CityInfo;
import android.os.Bundle;
import android.app.Activity;
import android.webkit.WebSettings;
import android.webkit.WebView;
import android.webkit.WebViewClient;
import android.provider.Settings.Secure;
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
WebView mywebview = (WebView) findViewById(R.id.webview);
mywebview.loadUrl("http://www.google.com");
//enabling Javascript
WebSettings webSettings = mywebview.getSettings();
webSettings.setJavaScriptEnabled(true);
//opening links in my webview. if you delete this line , any link pressed will cause the browser to start
mywebview.setWebViewClient(new WebViewClient());
}
}
为了获得设备ID,我读到我应该做这样的事情:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);
但是我不明白应该在哪里放置 android_id 代码,因为我总是出错。
错误是:
Multiple markers at this line:
- The method getcontext() is undefined for the type MainActivity
- Illegal modifier for parameter android_id; only final is permitted