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需要有关此作业的帮助：

**使用四个全局变量

foundCount  = 0
searchCount = 0
names = [ "Mary", "Liz", "Miles", "Bob", "Fred"]
numbers = [ 4, 17, 19]
def find(item):
    ....
def result():
    ....

为这两个函数的主体编写代码：

find()

接受一个参数，它在全局名称列表中查找，如果在那里找不到，则在数字列表中查找。

始终递增 searchCount，无论是否找到该项目

如果找到该项目，它会增加 foundCount 并酌情打印“Found in Names”或“Found in Numbers”。

如果找不到项目，则显示“未找到”

results() 这没有参数。它打印搜索计数的摘要：例如“总搜索：6，找到的项目：4，未找到：2”**

样品运行

**======= Loading Program =======
>>> find("mary")
 Not found
>>> find("Mary")
 Found in names
>>> find(0)
 Not found
>>> find(19)
 Found in numbers
>>> results()
  ***** Search Results *****
 Total searches:  4
 Total matches :  2
 Total not found: 2**

到目前为止我所做的是：

**

foundCount  = 0
searchCount = 0
names = [ "Mary", "Liz", "Miles", "Bob", "Fred"]
numbers = [ 4, 17, 19]
def find(item):
    global foundcount
    if item == "Mary":
      printNow("Found in names")
    elif item == "Liz":
      printNow("Found in names")
    elif item == "Miles":
      printNow("Found in names")
    elif item == "Bob":
      printNow("Found in names")
    elif item == "Fred":
      printNow("Found in names")
    elif item == "4":
      printNow("Found in numbers")
    elif item == "17":
      printNow("Found in numbers")
    elif item == "19":
      printNow("Found in numbers")
    else: printNow("Not Found")

def result():

**

我需要 def result() 函数的帮助，以便我可以在三天内完成这项作业并为我的数学考试学习.. 需要帮助来完成这项作业，因为它明天到期:(....

4

1 回答 1

1

使用in运算符：

def find(item):
    global foundcount

    if item in names:
        foundCount += 1
        printNow("Found in names")
    elif item in numbers:
        foundCount += 1
        printNow("Found in numbers")
    else:
        printNow("Not Found")

至于result，您可以使用以下print功能：

print('Found Items:', foundCount)
于 2013-04-04T01:57:03.947 回答