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我已将我的注册脚本从 mysql 转换为 mysqli。我像mysql一样工作得很好，但是现在它给了我错误

Commands out of sync; you can't run this command now

这是我用来注册用户的功能

function register_user($register_data) { 
global $myConnection;
array_walk($register_data, 'array_sanitize'); 
//Make the array readable and seperate the fields from data 
$fields = '`' . implode('`, `', array_keys($register_data)) . '`'; 
$data = '\'' . implode('\', \'', $register_data) . '\''; 
//Insert the data and email an activation email to the user 
mysqli_query($myConnection, "INSERT INTO `members` ($fields) VALUES ($data)") or die(mysqli_error($myConnection)); 
email($register_data['mem_email'], 'Activate your account', "Hello " . $register_data['mem_first_name'] . ",\n\nThank you for creating an account with H Fencing. Please use the link below to activate your account so we can confirm you identity:\n\nhttp://blah.blah.co.uk/activate.php?mem_email=" . $register_data['mem_email'] . "&email_code=" . $register_data['email_code'] . "\n\n - David & Jay "); 
}

电子邮件从我的阵列中发送正确的数据。但是没有数据插入到数据库中，我得到了上面提到的错误。我以前从未遇到过这个错误。

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1 回答 1

10

如果您的命令不同步；您现在无法在客户端代码中运行此命令，您正在以错误的顺序调用客户端函数。

例如，如果您正在使用 mysql_use_result() 并在调用 mysql_free_result() 之前尝试执行新查询，则可能会发生这种情况。如果您尝试执行两个返回数据的查询而不在两者之间调用 mysql_use_result() 或 mysql_store_result() ，也会发生这种情况。

从这里： http ://dev.mysql.com/doc/refman/5.0/en/commands-out-of-sync.html

更新

如果您为查询创建一个变量并将变量直接粘贴到 MySQL Workbench 之类的东西中，您可以在执行之前检查语法。

<?php
            function myConnection(){
              $myConnection = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
              return $myConnection;
            }   


    function register_user($register_data) { 
        array_walk($register_data, 'array_sanitize'); 
        //Make the array readable and seperate the fields from data 
        $fields = '`' . implode('`, `', array_keys($register_data)) . '`'; 
        $data = "'" . implode("', '", $register_data) . "'"; 
        //Insert the data and email an activation email to the user 
        $query = "INSERT INTO `members` ($fields) VALUES ($data)";
                    $myNewConnection = myConnection();          

                    if($result = mysqli_query($myNewConnection, $query)){ 
        email($register_data['mem_email'], 'Activate your account', "Hello " . $register_data['mem_first_name'] . ",\n\nThank you for creating an account with H Fencing. Please use the link below to activate your account so we can confirm you identity:\n\nhttp://blah.blah.co.uk/activate.php?mem_email=" . $register_data['mem_email'] . "&email_code=" . $register_data['email_code'] . "\n\n - David & Jay "); 
        mysqli_free_result($result);
         return ("Success");
        } else {
            echo $query;
            die(mysqli_error($myNewConnection));
        } 

    }

?>
于 2013-04-03T21:53:25.303 回答