您可以itertools.groupby()
为此使用,这是一个示例:
from itertools import groupby
# this just sets up some byte strings to use, Python 2.x version is below
# instead of this you would use f1 = open('some_file', 'rb').read()
f1 = bytes(int(b, 16) for b in 'FF FF FF FF 00 00 00 00 FF FF 44 43 42 41 FF FF'.split())
f2 = bytes(int(b, 16) for b in '41 42 43 44 00 00 00 00 44 43 42 41 40 39 38 37'.split())
matches = []
for k, g in groupby(range(min(len(f1), len(f2))), key=lambda i: f1[i] == f2[i]):
if k:
pos = next(g)
length = len(list(g)) + 1
matches.append((pos, length))
或者使用列表推导与上述相同:
matches = [(next(g), len(list(g))+1)
for k, g in groupby(range(min(len(f1), len(f2))), key=lambda i: f1[i] == f2[i])
if k]
如果您使用的是 Python 2.x,以下是示例的设置:
f1 = ''.join(chr(int(b, 16)) for b in 'FF FF FF FF 00 00 00 00 FF FF 44 43 42 41 FF FF'.split())
f2 = ''.join(chr(int(b, 16)) for b in '41 42 43 44 00 00 00 00 44 43 42 41 40 39 38 37'.split())