好的,我正在尝试使用此计数函数来计算 case 语句的不同部分。这是现在的工作代码。它会告诉我有人从哪一年开始上学。学年的细分方式是 200703 是 07 年夏季,200801 是 07 年秋季,200802 是 08 年春季。所以案例陈述给了我一个学生开始的学年。我只需要一种简单的方法来计算每个学年有多少一年级学生。我尝试在 case 语句周围使用 Count 并尝试设置不同的方法来计算它,但总是遇到聚合函数错误。任何帮助都会很棒。我在 SQL Server 2008 R2 中写这个
SELECT DISTINCT dbo.student_crs_hist.id_num,
sum(dbo.student_crs_hist.credit_hrs) as 'tot_credit_hrs',
min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE) as 'first_year',
'Year' = CASE
WHEN min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE)in ('200703','200801','200802') Then '20007-2008'
WHEN min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE)in ('200803','200901','200902') Then '20008-2009'
WHEN min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE)in ('200903','201001','201002') Then '20009-2010'
WHEN min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE)in ('201003','201101','201102') Then '2010-2011'
Else '2011-2012'
END
FROM dbo.student_crs_hist,
dbo.degree_history
WHERE dbo.student_crs_hist.id_num = dbo.degree_history.id_num and
((dbo.STUDENT_CRS_HIST.YR_CDE in ('2007') and dbo.STUDENT_CRS_HIST.TRM_CDE in ('03')) OR
(dbo.student_crs_hist.yr_cde in ( '2008','2009','2010','2011') AND dbo.student_crs_hist.trm_cde in ( '01','02','03' ))OR
(dbo.STUDENT_CRS_HIST.YR_CDE in ('2012') and dbo.STUDENT_CRS_HIST.TRM_CDE in ('01','02'))) and
dbo.student_crs_hist.transaction_sts in ( 'C','H' ) AND
dbo.student_crs_hist.grade_cde in ( 'A','B','C' ) AND
dbo.degree_history.major_1 = 'ASBD' and
dbo.student_crs_hist.adv_req_cde not in ('COL081','EGL082','EGL092','EGL093','MAT091','MAT092','MAT093','COM091','EGL100','REA100')
Group By
dbo.STUDENT_CRS_HIST.ID_NUM
Having
sum(dbo.student_crs_hist.credit_hrs) >= '30' and
(min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE) = '200703' or
min(dbo.student_crs_hist.yr_cde) in ('2008','2009','2010','2011') or
MIN(dbo.student_crs_hist.yr_cde+dbo.student_crs_hist.trm_cde) in ('201201','201202'))
Order By
min(dbo.student_crs_hist.yr_cde+dbo.STUDENT_CRS_HIST.TRM_CDE)