4

由于某种原因,此UPDATE查询永远挂起。如果我替换为SELECT- 它会立即得到结果。

UPDATE table1 AS t1
INNER JOIN
(
    SELECT count(*) as total, left(number,7) as prefix, outcome FROM table1
    where outcome like '%Passed%'
    group by prefix 
    order by total desc limit 200
) AS t2 
ON t2.prefix = left(t1.number,7) AND t1.outcome = 'Fail'
SET t1.outcome = '', t1.status = 'NEW'

那里有什么问题?

4

3 回答 3

2

尝试将ORDER BYandLIMIt移到UPDATE. 就像是:

UPDATE table1 AS t1
INNER JOIN
(
    SELECT count(*) as total, left(number,7) as prefix, outcome FROM table1
    where outcome like '%Passed%'
    group by prefix 
) AS t2 ON t2.prefix = left(t1.number, 7) AND t1.outcome = 'Fail'
SET t1.outcome = '', t1.status = 'NEW'
order by total desc 
limit 200;

请参阅UPDATE.

于 2013-04-03T12:19:09.923 回答
1

我会尝试这样的事情:

UPDATE table1
SET
  table1.outcome = '',
  table1.status = 'NEW'
WHERE
  outcome = 'Fail'
  AND 
  left(number,7) IN (SELECT * FROM (
    SELECT left(number,7) as prefix
    FROM table1
    WHERE outcome like '%Passed%'
    GROUP BY prefix 
    ORDER BY COUNT(*) desc limit 200
    ) s
  )

在此处查看小提琴。

于 2013-04-03T12:29:28.473 回答
0

你能更新你加入的专栏吗?即,t1.outcome

将过滤器表达式t1.outcome = 'Fail'移出JOIN和移入WHERE子句。

UPDATE table1 AS t1
INNER JOIN
(
    SELECT count(*) as total, left(number,7) as prefix, outcome FROM table1
    where outcome like '%Passed%'
    group by prefix 
    order by total desc limit 200
) AS t2 
ON t2.prefix = left(t1.number,7)
SET t1.outcome = '', t1.status = 'NEW'
WHERE t1.outcome = 'Fail'
于 2013-04-03T12:27:39.527 回答