当用户单击链接时，我正在尝试传递查询字符串。
这样在它指向的下一页将从 mysql 检索特定的产品（查询字符串参数）详细信息。
下面是我的代码，我该怎么做呢？
当前页面：
<?php
// Write a series of five PHP statements to retrieve the data for all product items in the database
// Write a statement to prepare the SQL SELECT statement
$sql = "SELECT skuCode, brand, model FROM productItem;";
// Write a statement to open a connection to MySQL server
$link = mysql_connect("localhost", "root", "password");
// Write a statement to select the required database
mysql_select_db("is1112t4q3", $link);
// Write a statement to send the SQL statement to the MySQL server for execution and retrieve the resultset
$resultset = mysql_query($sql);
// Write a statement to close the connection
mysql_close($link);
// Write a suitable expression for the while loop to iterate through each data row in the resultset.
// Each data row represents one product item that you need to display
while($row = mysql_fetch_array($resultset))
{
// Write a echo command to display the summary information for each product item. The required attributes are
// indicated in the HTML table header row.
// The image that is displayed should be the first image of each product item, e.g., MP300001_1.jpg.
// The Action column should contain a hyperlink to viewProductItem.php where user can view the complete product information
// of the selected product item.
// You need to use a query string parameter to pass the SKU Code of the required product item to viewProductItem.php
echo("<tr><td>".$row[0].
"</td><td>".$row[1].
"</td><td>".$row[2].
"</td><td>"."<img src=images/".$row["skuCode"]."_1.jpg>".
"</td><td><a href=viewProductItem.php?var=skuCode>View</a>".
"</td></tr>");
}
?>
下一页，此页面应检索单击链接时从上一页传递的 skuCode <a href=viewProductItem.php?var=skuCode>View</a>。
<?php
// Complete the if expression using the isset function to determine whether the query string parameter skuCode has been provided
if(isset($_GET["skuCode"]))
{
// Write a series of five PHP statements to retrieve the data for the selected product item from the database
// Write a statement to prepare the SQL SELECT statement. The SQL statement should have a WHERE condition
$sql = "SELECT * FROM productItem WHERE skuCode = '".mysql_real_escape_string($_GET["skuCode"])."';";
// Write a statement to open a connection to MySQL server
$link = mysql_connect("localhost", "root", "password");
// Write a statement to select the required database
mysql_select_db("is1112t4q3", $link);
// Write a statement to send the SQL statement to the MySQL server for execution and retrieve the resultset
$resultset = mysql_query($sql);
// Write a statement to close the connection
mysql_close($link);
// The statement below will retrieve the first data row in the resultset.
// Note that we are only expecting at most one data row since we are filtering by the primary key skuCode
// mysql_fetch_array will an array of values corresponding to the fetched data row.
// If there is no matching data row, mysql_fetch_array will return FALSE
$row = mysql_fetch_array($resultset);
if($row)
{
// Write a series of echo commands to print out the complete information of the selected product item using a HTML table
echo("<tr><td>".$row[0].
"</td><td>".$row[1].
"</td><td>".$row[2].
"</td><td>"."<img src=images/".$row["skuCode"]."_1.jpg>".
"</td><td><a href=viewProductItem.php>View</a>".
"</td></tr>");
}
}
else
{
echo("<h3 style=\"color: red;\">Product item ".$_GET["skuCode"]." does not exist</h3>");
}
}
else
{
echo("<h3 style=\"color: red;\">No product item has been selected</h3>");
}