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我正在使用这种方法检查网络状态：

public boolean hasConnection() {
    ConnectivityManager cm = (ConnectivityManager) SigninActivity.this
            .getBaseContext()
            .getSystemService(Context.CONNECTIVITY_SERVICE);

    NetworkInfo wifiNetwork = cm
            .getNetworkInfo(ConnectivityManager.TYPE_WIFI);
    if (wifiNetwork != null && wifiNetwork.isConnected()) {
        return true;
    }

    NetworkInfo mobileNetwork = cm
            .getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
    if (mobileNetwork != null && mobileNetwork.isConnected()) {
        return true;
    }

    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork != null && activeNetwork.isConnected()) {
        return true;
    }

    return false;
}

然后使用此类为 json 调用 web 服务：

    public class JSONParser {

InputStream is = null;
JSONObject jObj = null;
String json = "";
HttpClient httpClient;

// constructor
public JSONParser() {

}

public JSONObject getJSONFromUrl(String url) {

    // Making HTTP request
    try { // defaultHttpClient DefaultHttpClient
        httpClient = new DefaultHttpClient();

        HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        reader.close();
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}
    }

但是该应用程序在非常慢的网络下崩溃，在正常情况下工作得很好。有人能提出更好的方法来避免强制关闭吗？

“我从 AsyncTask 类的 doInBackground 方法中调用了这个类。 提前致谢

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0 回答 0