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我正在创建一个 zip 文件并下载它。我能够下载所有文件文件而不会出现任何错误。但是，当我试图仅压缩“finaldebrief”文件夹。我想直接在 zip 文件中获取“finaldebrief”文件夹。有人可以帮我吗。提前致谢。

这是我的代码

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    int workshopid = Integer.parseInt(request.getParameter("currentworkshopid"));

    javax.servlet.ServletContext context = getServletConfig().getServletContext();
    String path = context.getRealPath("finaldebrief");

    try 
    { 
        response.setContentType("application/zip");
        response.setHeader("Content-Disposition", "attachment;filename=finaldebrief.zip");

        ZipOutputStream zos = new 
               ZipOutputStream(response.getOutputStream()); 

        zipDir(path + "/", zos); 

        zos.close(); 
    } 
    catch(Exception e) 
    { 
        e.printStackTrace();
    } 

}

public void zipDir(String dir2zip, ZipOutputStream zos) 
{
    try 
    { 
        //create a new File object based on the directory we have to zip File    
        File zipDir = new File(dir2zip); 
        //get a listing of the directory content 
        String[] dirList = zipDir.list(); 
        byte[] readBuffer = new byte[2156]; 
        int bytesIn = 0; 
        //loop through dirList, and zip the files 
        for(int i=0; i<dirList.length; i++) 
        { 
            File f = new File(zipDir, dirList[i]); 
            if(f.isDirectory()) 
            { 
                //if the File object is a directory, call this 
                //function again to add its content recursively 
                String filePath = f.getPath();
            //  String filePath = f.getCanonicalPath();

                zipDir(filePath, zos);
                //loop again 
                continue; 
            } 
            //if we reached here, the File object f was not  a directory 
            //create a FileInputStream on top of f 
            FileInputStream fis = new FileInputStream(f); 
            // create a new zip entry 
            ZipEntry anEntry = new ZipEntry(f.getPath()); 
            //place the zip entry in the ZipOutputStream object 
            zos.putNextEntry(anEntry); 
            //now write the content of the file to the ZipOutputStream 
            while((bytesIn = fis.read(readBuffer)) != -1) 
            { 
                zos.write(readBuffer, 0, bytesIn); 
            } 
            //close the Stream 
            fis.close(); 
        } 
    } 
    catch(Exception e) 
    { 
        e.printStackTrace(); 
    } 
}
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1 回答 1

3

行内

ZipEntry anEntry = new ZipEntry(f.getPath());

您指定 zip 文件中的路径（即f.getPath()）。如果您想要更短的路径或根本没有路径，只需操纵这部分（例如f.getName()）。

于 2013-04-03T06:28:42.543 回答