我正在使用 instagram ruby gem。如果我在下面做超过 2 个请求，我得到的错误是什么。
现在，对于前两个请求，它显示了这个
Processing by HomesController#index as JS
Processing by HomesController#index as */*
因此，当第三个请求现在发生时，它会误入（如上所述）这个
Completed 500 Internal Server Error in 4525ms
JSON::ParserError (757: unexpected token at '<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" class="hl-en not-logged-in ">
<head>
<meta charset="UTF-8" />
<title>Page Not Found • Instagram</title>
<meta name="robots" content="noimageindex" />
<link rel="Shortcut Icon" type="image/x-icon" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/images/ico/favicon.ico" />
<meta name="apple-mobile-web-app-capable" content="yes" />
<meta name="apple-mobile-web-app-status-bar-style" content="black" />
<link rel="apple-touch-icon-precomposed" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/images/ico/apple-touch-icon-precomposed.png" />
<link rel="apple-touch-icon-precomposed" sizes="72x72" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/images/ico/apple-touch-icon-72x72-precomposed.png" />
<link rel="apple-touch-icon-precomposed" sizes="114x114" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/images/ico/apple-touch-icon-114x114-precomposed.png" />
<link rel="apple-touch-icon-precomposed" sizes="144x144" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/images/ico/apple-touch-icon-144x144-precomposed.png" />
<meta name="viewport" content="width=device-width, user-scalable=no, initial-scale=1.0, minimum-scale=1.0, maximum-scale=1.0" />
<script type="text/javascript" src="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/scripts/jquery.js"></script>
<script type="text/javascript" src="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/scripts/bluebar.js"></script>
<script type="text/javascript" src="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/cache/strings/strings_en.js"></script>
<script>
window._csrf_token = 'NOTPROVIDED';
window._jscalls = [
];
</script>
<script type="text/javascript" src="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/cache/polyfills/polyfill_old.js"></script>
<script data-main="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/cache/modules/main.js" src="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/scripts/require.js"></script>
<link rel="stylesheet" type="text/css" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/cache/bluebar/bluebar_new.css" />
<link rel="stylesheet" type="text/css" href="//d36xtkk24g8jdx.cloudfront.net/bluebar/f4f8a28/cache/distillery/dialog-main.css"/>
</head>
<body class=" p-error dialog-404">
<div class="root">
<div class="page">
<header class="top-bar top-bar-new">
<div class="top-bar-wrapper">
<h1 class="logo"><a href="/">Instagram</a></h1>
<div class="top-bar-left">
<ul class="top-bar-actions">
<li>
<a class="top-bar-home" href="/" label=Home><i></i></a>
</li>
</ul>
<div class="top-bar-search" id="top-bar-search">
</div>
</div>
<div class="top-bar-right account-state" id="top_bar_right">
<ul class="top-bar-actions">
<li id="link_profile" class="link-signin">
<a href="javascript:;" class="loginLink">
<i></i>
<strong>Log in</strong>
</a>
</li>
</ul>
</div>
</div>
</header> <!-- .top-bar -->
<div class="main">
<div class="error-container">
<h2>Page Not Found</h2>
<p>This page could not be found.<br />You might have followed an incorrect link.</p>
</div>
</div> <!-- .main -->
</div> <!-- .page -->
<footer class="page-footer" role="contentinfo">
<div class="wrapper">
<nav>
<ul>
<li><a href="/about/us/">About us</a></li>
<li><a href="http://help.instagram.com/">Support</a></li>
<li><a href="http://blog.instagram.com/">Blog</a></li>
<li><a href="/developer/">API</a></li>
<li><a href="/about/jobs/">Jobs</a></li>
<li><a href="/about/legal/privacy/">Privacy</a></li>
<li><a href="/about/legal/terms/">Terms</a></li>
</ul>
</nav>
<p class="copyright">© 2013 Instagram</p>
</div>
</footer>
<div id="reactModalMountPoint"></div>
</div> <!-- .root -->
<script type="text/javascript">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-18105282-1']);
_gaq.push(['_setDomainName', 'none']);
_gaq.push(['_setAllowLinker', true]);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>
</body>
</html>'
我认为标题有问题？既然我是通过ajax来做这个过程的，我怎么能强制它通过JS来处理呢？因为这似乎在这里工作我相信。
这是我的ajax代码
{
$.ajax({
url: /home,
method: "post",
data: {
// data goes here
},
success: function(html)
{
if(html)
{
// html goes here
}else
{
// html goes here</center>');
}
}