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我正在开发一个项目，我必须从以下代码创建一个 SOAP 请求对象：

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:mod="http://www.tmforum.org/xml/tip/model" xmlns:prob="http://www.tmforum.org/xml/tip/cbe/problem" xmlns:geo="http://www.tmforum.org/xml/tip/cbe/loc/geo" xmlns:loc="http://www.tmforum.org/xml/tip/cbe/loc" xmlns:tt="http://www.tmforum.org/xml/tip/cbe/tt" xmlns:ent="http://www.tmforum.org/xml/tip/internal/entity" xmlns:ext="http://www.tmforum.org/xml/tip/cbe/problem/extensions">
   <soapenv:Header/>
   <soapenv:Body>
      <mod:retrieveProblemRequest>
         <!--Optional:-->
         <mod:customerProblem>
            <!--Optional:-->
            <prob:problemId>0005004426</prob:problemId>

         </mod:customerProblem>
      </mod:retrieveProblemRequest>
   </soapenv:Body>
</soapenv:Envelope>

我正在使用 KSOAP2 来创建请求对象，但在分配命名空间时遇到了问题，因此发送的请求总是不正确的。

请向我提供在 android 中将此 SoapRequest 转换为 SoapObject 的代码。

编辑：我的代码如下：

private static String SOAP_ACTION1 = "/BusinessServices/Inbound/TIP_R4GCanonicalModel_model_problemservicev1dot3-service0.serviceagent/ProblemServiceV1dot3Endpoint0/retrieveProblem";
    private static String REQUEST_TARGET_NAMESAPCE="http://xmlns.example.com/1362214927265/";
    private static String TARGET_NAMESPACE_MOD = "http://www.tmforum.org/xml/tip/model/";
    private static String NAMESPACE_PROB="http://www.tmforum.org/xml/tip/cbe/problem/";
    private static String METHOD_NAME = "retrieveProblem";
    private static String URL = "http://10.128.28.44:10005/BusinessServices/Inbound/ProblemService_proxy.serviceagent/ProblemServiceV1dot3Endpoint0";
public static String LOG_TAG = "SOAPRequestResponseActivity";


    @Override
    public void onCreate(Bundle savedInstanceState)

    {

        super.onCreate(savedInstanceState);
            setContentView(R.layout.main);
            btnFar = (Button) findViewById(R.id.btnFar);
        btnFar.setOnClickListener(new View.OnClickListener()

        {
            @Override
            public void onClick(View v)

            {

                // Initialize soap request + add parameters

                SoapObject request = new SoapObject(REQUEST_TARGET_NAMESAPCE,METHOD_NAME);

                SoapObject retrieveInfo=new SoapObject(TARGET_NAMESPACE_MOD,"retrieveProblemRequest");

                SoapObject customerObject=new SoapObject(TARGET_NAMESPACE_MOD, "customerProblem");

                PropertyInfo info=new PropertyInfo();
                info.setNamespace(NAMESPACE_PROB);
                info.setName("problemId");
                info.setValue("0005004426");

                customerObject.addProperty(info);
                retrieveInfo.addSoapObject(customerObject);
                request.addSoapObject(retrieveInfo);

   Log.i(LOG_TAG, "===Request soap object after params=="
                        + request.toString());

                // Declare the version of the SOAP request

                SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                        SoapEnvelope.VER11);


                envelope.implicitTypes=true;
                envelope.setOutputSoapObject(request);

                try {

                    HttpTransportSE androidHttpTransport = new HttpTransportSE(
                            URL);



                    ArrayList<HeaderProperty> headerProperty = new ArrayList<HeaderProperty>();

                    headerProperty.add(new HeaderProperty("SOAPAction", "/BusinessServices/Inbound/TIP_R4GCanonicalModel_model_problemservicev1dot3-service0.serviceagent/ProblemServiceV1dot3Endpoint0/retrieveProblem"));

                    androidHttpTransport.call(SOAP_ACTION1, envelope,headerProperty);

只要调用方法，它就会抛出异常 HttpRequestFailed，错误代码为 500。由于请求不正确，服务器无法解析它。

请为我提供适当的解决方案。

4

1 回答 1

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我遇到了一个名为ksoap2-android的库，它非常有帮助，你可以试试这个。这是我用来调用 web 方法的类文件

 public class CallSOAP {

private String SOAP_ACTION="your action url";
private String OPERATION_NAME="";//The web method OR web service you are going to call
private final String WSDL_TARGET_NAMESPACE=SOAP_ACTION;
private  final String SOAP_ADDRESS=Configuration.WEB_SERVICE_URL;//ip-address of serever where you host your service 
private Exception exception;
private String ErrorMsg="";
private String TERST_URL="" ;
public Object call(String MethodeName,ArrayList<PropertyInfo> Parameters){

  this.OPERATION_NAME=MethodeName;
  SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE, OPERATION_NAME);
 if(Parameters != null && Parameters.size()>0){
   for(PropertyInfo propertyInfo : Parameters){
      request.addProperty(propertyInfo);
 }
}

SoapSerializationEnvelope  envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet= true;
envelope.setOutputSoapObject(request);
HttpTransportSE httpTransport =null;
if(!this.TERST_URL.equals(""))
  httpTransport = new HttpTransportSE(this.TERST_URL);
else
  httpTransport = new HttpTransportSE(SOAP_ADDRESS);
 Object Response =null;
 try{
    httpTransport.call(SOAP_ACTION+OPERATION_NAME, envelope);
    Response=envelope.getResponse();
  }
 catch (SocketTimeoutException ex) {
     this.ErrorMsg="Unable to connect";
      Response=null;
     this.exception=ex;
  }
  catch (IOException ie) {
   this.ErrorMsg="Unable to connect";
  Response=null;
   this.exception=ie;
  }
   catch (Exception e) {
    this.ErrorMsg="Unable to connect";
    Response=null;
    this.exception=e;
 }
      return Response;
   }
}

请注意，我使用的是用 ASP.NET 框架编写的 Web 服务。这就是我提供的原因

envelope.dotNet= true;

供参考：请参阅本教程

并看到这个问题

于 2013-04-02T08:41:06.137 回答