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我的数据库中有一个简单的日志表。对于每个页面访问，插入一行。现在我想总结一下今天和昨天的某个专栏。

我尝试了以下查询：

SELECT Sum(CASE 
             WHEN `time` > 1364767200 THEN `sqlquerycount` 
           end) AS `today`, 
       Sum(CASE 
             WHEN `time` BETWEEN 1364684400 AND 1364767200 THEN `sqlquerycount` 
           end) AS `yesterday` 
FROM   `log`

以下 PHP 脚本的结果：

$sql = "SELECT 
        SUM(CASE WHEN `time` > ".strtotime("today")." THEN `sqlQueryCount` END) AS `today`,
        SUM(CASE WHEN `time` BETWEEN ".strtotime("yesterday")." AND ".strtotime("today")." THEN `sqlQueryCount` END) AS `yesterday`
    FROM `log`";

“昨天”仍为 NULL，但我认为此查询没有任何问题。任何的想法？

4

1 回答 1

2

我敢打赌

$sql = "SELECT 
        SUM(CASE WHEN `time` > ".strtotime("today")." THEN `sqlQueryCount` ELSE 0 END) AS `today`,
        SUM(CASE WHEN `time` BETWEEN ".strtotime("yesterday")." AND ".strtotime("today")." THEN `sqlQueryCount` ELSE 0 END) AS `yesterday`
    FROM `log`";

...提供sqlQueryCount的是您要进行总和的列！

于 2013-04-01T20:30:05.443 回答