2

我想要做的应该很简单。我认为。我想使用反射来确定案例类构造函数的参数的名称和类型。下面是一个 REPL 交互。您可以跳到调用“paramss”的末尾。我想检查内部列表中的符号或进行模式匹配，以确定“名称”确实是一个字符串，而“年龄”是一个 Int。

我怎么做？

scala> case class Person(name: String, age: Int)
defined class Person

scala> import scala.reflect.runtime.universe._
import scala.reflect.runtime.universe._

scala> typeOf[Person]
res0: reflect.runtime.universe.Type = Person

scala> typeTag[Person]
res1: reflect.runtime.universe.TypeTag[Person] = TypeTag[Person]

scala> res1.mirror
res2: reflect.runtime.universe.Mirror = JavaMirror with scala.tools.nsc.interpreter.IMain$TranslatingClassLoader@2daf73a4 of type class scala.tools.nsc.interpreter.IMain$TranslatingClassLoader with classpath [(memory)] and parent being scala.tools.nsc.util.ScalaClassLoader$URLClassLoader@59d12b6a of type class scala.tools.nsc.util.ScalaClassLoader$URLClassLoader with classpath [file:/Library/Java/JavaVirtualMachines/jdk1.7.0_13.jdk/Contents/Home/jre/lib/resources.jar,file:/Library/Java/JavaVirtualMachines/jdk1.7.0_13.jdk/Contents/Home/jre/lib/rt.jar,file:/Library/Java/JavaVirtualMachines/jdk1.7.0_13.jdk/Contents/Home/jre/lib/jsse.jar,file:/Library/Java/JavaVirtualMachines/jdk1.7.0_13.jdk/Contents/Home/jre/lib/jce.jar,file:/Library/Java/JavaVirtualMachines/jdk1.7.0_13.jdk/Contents/Home/j...
scala> res1.tpe
res3: reflect.runtime.universe.Type = Person

scala> res3.typeSymbol.asClass
res4: reflect.runtime.universe.ClassSymbol = class Person

scala> res2.reflectClass(res4)
res5: reflect.runtime.universe.ClassMirror = class mirror for Person (bound to null)

scala> res3.declaration(reflect.runtime.universe.nme.CONSTRUCTOR)
res6: reflect.runtime.universe.Symbol = constructor Person

scala> res6.asMethod
res7: reflect.runtime.universe.MethodSymbol = constructor Person

scala> res7.paramss
res8: List[List[reflect.runtime.universe.Symbol]] = List(List(value name, value age))
4

3 回答 3

1

That's how you get a Type object representing the type of your constructor parameter:

val ctorParamss = typeOf[Person].member(nme.CONSTRUCTOR).asMethod.paramss
val typeOfNameParam: Type = paramss(0)(0).typeSignature

Now that you have that object, you can perform various tests on it:

typeOfNameParam =:= typeOf[Int]      // is this type an Int ?
typeOfNameParam <:< typeOf[Number]   // is this type java.lang.Number or its subtype ?
于 2013-04-01T12:24:42.030 回答
1

使用SMirror：

scala> import net.fwbrasil.smirror._
import net.fwbrasil.smirror._

scala> implicit val mirror = scala.reflect.runtime.currentMirror
mirror: reflect.runtime.universe.Mirror = JavaMirror with scala.t...

scala> case class Person(name: String, age: Int)
defined class Person

scala> val clazz = sClassOf[Person]
clazz: net.fwbrasil.smirror.SClass[Person] = Person

scala> val ctor = clazz.constructors.head
ctor: net.fwbrasil.smirror.SConstructor[Person] = <init>(name: java.lang.String, age: scala.Int): Person

scala> ctor.parameters
res0: List[ctor.SParameterType] = List(name: java.lang.String, age: scala.Int)

scala> ctor.parameters.head.sClass == sClassOf[String]
res2: Boolean = true
于 2013-04-01T14:03:59.780 回答
0

有趣的是你应该问！这正是我现在正在做的事情。

所以，首先，你有参数。因此，您必须处理如何/是否支持多个参数列表。下面是一些坚持只使用一个参数列表的代码，并捕捉到了这一点：

val ctorParams  : List[Symbol] = ctorParamss match {
  case Nil => {
println("Warning: Trying to populate a no-arg constructor from a Map. No data will be used.");
Nil;
  }
  case head :: Nil => head;
  case _ => throw new UnsupportedOperationException("Cannot populate a constructor with multiple param lists from a Map.");
}

现在我们需要名称和类型名称：

val ctorParamNames = ctorParams.map( _.name.toString.trim );
val ctorParamTypeNames = ctorParams.map( _.typeSignature.baseClasses(0).fullName.toString.trim );

此刻，我仍在为此努力，但到目前为止，这对我有用。祝你好运！

于 2013-04-01T06:05:16.240 回答