我需要做一个会话过滤器。localhost:8080/Project/faces/index.xhtml是登录名。如果登录成功,将重定向用户app/conta.xhtml
,但如果用户直接在地址栏中写入 localhost:8080/Project/faces/app/conta.xhtml而未登录,则必须再次重定向index.xhtml。
app/* 中的所有页面必须在没有成功登录的情况下才能访问。
我的课LoginFilter
在包里filtro
@WebFilter("/app/*")
public class LoginFilter implements Filter {
@Override
public void init(FilterConfig config) throws ServletException {
// If you have any <init-param> in web.xml, then you could get them
// here by config.getInitParameter("name") and assign it as field.
}
@Override
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
HttpServletResponse response = (HttpServletResponse) res;
HttpSession session = request.getSession(false);
if (session == null || session.getAttribute("idUsuario") == null) {
response.sendRedirect(request.getContextPath() + "../index.xhtml"); // No logged-in user found, so redirect to login page.
} else {
chain.doFilter(req, res); // Logged-in user found, so just continue request.
}
}
@Override
public void destroy() {
// If you have assigned any expensive resources as field of
// this Filter class, then you could clean/close them here.
}
}
我的 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>faces/index.xhtml</welcome-file>
</welcome-file-list>
<filter>
<filter-name>Login Filter</filter-name>
<filter-class>filtro.LoginFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>Login Filter</filter-name>
<url-pattern>/app/*</url-pattern>
</filter-mapping>
</web-app>
尽管如此,我还是可以进入 /faces/app/conta.xhtml 并正常访问!
这是我的登录验证代码= validarLogin()
BeanUsuarios.java
@ManagedBean
@ViewScoped
public class BeanUsuarios {
private Usuario usuario;
public Usuario getUsuario() {
return usuario;
}
public void setUsuario(Usuario usuario) {
this.usuario = usuario;
}
@PostConstruct
public void BeanUsuario(){
if(getUsuario()==null){
usuario = new Usuario();
}
}
public void validarLogin(){
UsuarioJpaController cUsuario = new UsuarioJpaController();
cUsuario.getEntityManager().createNamedQuery("Usuario.findByLogin").setParameter("login", this.usuario.getLogin()).getSingleResult();
if(usuario != null){
if(usuario.getSenha().equals(this.usuario.getSenha())){
FacesContext fc = FacesContext.getCurrentInstance();
HttpSession session = (HttpSession) fc.getExternalContext().getSession(false);
session.setAttribute("idUsuario", this.usuario.getId());
try {
FacesContext.getCurrentInstance()
.getExternalContext()
.redirect("app/conta.xhtml");
} catch (IOException ex) {
Logger.getLogger(BeanUsuarios.class.getName()).log(Level.SEVERE, null, ex);
}
}else{
}
}
}
}