What is the most efficient way to create list of the same number with n elements?
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15
number = 1
elements = 1000
thelist = [number] * elements
>>> [1] * 10
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
NB: Don't try to duplicate mutable objects (notably lists of lists) like that, or this will happen:
In [23]: a = [[0]] * 10
In [24]: a
Out[24]: [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0]]
In [25]: a[0][0] = 1
In [26]: a
Out[26]: [[1], [1], [1], [1], [1], [1], [1], [1], [1], [1]]
If you are using numpy, for multidimensional lists numpy.repeat
is your best bet. It can repeat arrays of all shapes over separate axes.
于 2013-03-30T23:01:48.853 回答